The problem asks about the transformation of the graph $y = |x|$ when it becomes $y = |x - 2|$, and specifically where the point $(2,0)$ moves under this transformation.

Explanation:

The equation $y = |x - 2|$ represents a horizontal shift of the graph $y = |x|$ to the right by 2 units. Here’s how the transformation works:

1. Any point $(x, y)$ on $y = |x|$ will move to the point $(x + 2, y)$ on $y = |x - 2|$.
2. The point $(2, 0)$ is already on the vertex of $y = |x - 2|$, because substituting $x = 2$ into $y = |x - 2|$ yields $y = 0$. Therefore, this point does not move.

Conclusion:

The correct answer is D. It did not move.

Let me know if you want more clarification or details on graph transformations!

Related Questions:

1. What happens to the graph of $y = |x|$ when it is shifted by $y = |x + 3|$?
2. How does the vertex of $y = |x - 2|$ compare to that of $y = |x|$?
3. What is the effect of combining vertical and horizontal shifts in an absolute value function?
4. How would the graph of $y = |x - 2| + 3$ look compared to $y = |x - 2|$?
5. What is the domain and range of $y = |x - 2|$?

Tip:

When analyzing graph transformations, always focus on how each change in the equation affects the position of the vertex and the general shape of the graph!