To solve this problem, we can use similar triangles. The pole and the tree, along with their shadows, form two right-angled triangles. Since both the pole and the tree are standing in the same sunlight, the angle of elevation of the sun is the same for both, meaning their triangles are similar.

Step 1: Set up the proportion

Let the height of the tree be $h$ meters. The pole's height is 33 meters, and the pole's shadow is 44 meters long. The tree's shadow is 1515 meters long.

We can set up the proportion as follows:

$\frac{\text{Height of Pole}}{\text{Length of Pole's Shadow}} = \frac{\text{Height of Tree}}{\text{Length of Tree's Shadow}}$

Substitute the known values:

$\frac{33}{44} = \frac{h}{1515}$

Step 2: Solve for $h$

Cross-multiply to solve for $h$:

$33 \times 1515 = 44 \times h$

$49995 = 44h$

Now, divide both sides by 44 to find $h$:

$h = \frac{49995}{44} = 1136.75$

Thus, the height of the tree is approximately 1136.75 meters.

However, there seems to be an error. I have incorrectly made the numbers seem unreasonable. Let me clarify