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1.7. Assuming that a heat pump has a coefficient of performance equal to 4, how much heat
could this device deliver to the interior of a building with 1 kWh of electricity.

The coefficient of performance (COP) of a heat pump is a measure of its efficiency, defined as the ratio of the heat delivered to the energy consumed. The formula is:

\[
\text{COP} = \frac{Q}{W}
\]

where:
- \( Q \) is the amount of heat delivered by the heat pump (in kWh),
- \( W \) is the amount of work or energy input (in kWh).

Given:
- COP = 4
- \( W = 1 \) kWh

We need to find the amount of heat \( Q \) that the heat pump can deliver.

Rearrange the formula to solve for \( Q \):

\[
Q = \text{COP} \times W
\]

Substitute the given values:

\[
Q = 4 \times 1 \text{ kWh} = 4 \text{ kWh}
\]

So, the heat pump could deliver **4 kWh** of heat to the interior of the building with 1 kWh of electricity.

Would you like more details or have any questions about this?

Here are 5 related questions:
1. How does the coefficient of performance (COP) of a heat pump change with outdoor temperature?
2. What are typical COP values for different types of heat pumps?
3. How do you calculate the seasonal performance factor (SPF) for a heat pump?
4. What is the relationship between the COP of a heat pump and its energy efficiency ratio (EER)?
5. How does the heat pump's performance compare to traditional heating systems?

**Tip:** The COP of a heat pump can vary depending on the temperature difference between the inside and outside of the building, so it's important to consider this when assessing efficiency.

Assuming that a heat pump has a coefficient of performance equal to 4, how much heat could this device deliver to the interior of a building with 1 kWh of electricity?

Discover how to calculate the heat delivered by a heat pump with a coefficient of performance (COP) of 4 using 1 kWh of electricity. This problem explores efficiency concepts and key formulas, making it ideal for high school students in Grades 10-12.

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