Math Problem Statement
Solution
Let's go through the problems one by one.
Problem 1:
You are asked to show that the given functions are harmonic in , i.e.,
For each of the following functions:
(a)
- Compute and .
- Compute and .
- Add the second partial derivatives and verify if the sum is zero.
(b)
- Repeat the same process as above: find the second partial derivatives with respect to and , and check if they sum to zero.
(c)
- This function involves a quotient, so apply the quotient rule when finding the partial derivatives.
- Verify if the Laplacian sums to zero.
Additionally, you are asked to find the harmonic conjugate for each function. Recall that if is analytic in , then and must satisfy the Cauchy-Riemann equations:
For each , solve these equations to find .
Problem 2:
You are asked to solve Laplace's equation in polar coordinates:
(a)
You need to derive Laplace's equation in polar coordinates and show it matches the provided form.
(b)
Show that is harmonic on the punctured plane , by substituting this into the polar Laplace equation and verifying it holds.
(c)
You need to show that has no conjugate harmonic function on , but does on the slit plane . This requires analyzing the behavior of and its branches.
Problem 3:
Evaluate the following integrals over the unit circle with the counterclockwise orientation:
(a)
This integral can be evaluated using the parametrization of the unit circle, , where .
(b)
Here, on the unit circle, so rewrite the integral using this expression and solve.
I will now proceed to solve each part. Do you have any specific part you'd like to focus on first?
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Math Problem Analysis
Mathematical Concepts
Harmonic functions
Laplace's equation
Polar coordinates
Cauchy-Riemann equations
Complex analysis
Formulas
Laplace's equation: ∇²u = 0
Harmonic functions: u_xx + u_yy = 0
Cauchy-Riemann equations
∂²u/∂r² + (1/r)∂u/∂r + (1/r²)∂²u/∂θ² = 0
Theorems
Harmonic Conjugate Theorem
Laplace's Equation
Green's Theorem in the plane
Suitable Grade Level
University level (Advanced calculus/complex analysis)
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