Hardy-Weinberg equilibrium the percentage of the  homozygous recessive genotype (aa) is 36%. Using that 36% 
calculate the following the frequency of the "a" allele.


To calculate the frequency of the "a" allele, we will use the Hardy-Weinberg equilibrium principle. The key formulae are:

1. \( p^2 + 2pq + q^2 = 1 \), where:
   - \( p^2 \) represents the frequency of the homozygous dominant genotype (AA),
   - \( 2pq \) represents the frequency of the heterozygous genotype (Aa),
   - \( q^2 \) represents the frequency of the homozygous recessive genotype (aa).

2. \( p + q = 1 \), where:
   - \( p \) is the frequency of the dominant allele (A),
   - \( q \) is the frequency of the recessive allele (a).

Given:
- The frequency of the homozygous recessive genotype (aa) is 36%, so \( q^2 = 0.36 \).

### Step 1: Find \( q \)
To find \( q \), we take the square root of \( q^2 \):
\[
q = \sqrt{0.36} = 0.6
\]
So, the frequency of the "a" allele is \( q = 0.6 \).

Would you like to calculate the frequency of the dominant allele "A" or explore more details?

Here are five related questions:
1. What is the frequency of the dominant allele (A)?
2. What is the frequency of the heterozygous genotype (Aa)?
3. How does the Hardy-Weinberg equilibrium apply to real-world populations?
4. Can you predict the next generation's genotype frequencies?
5. What assumptions are required for a population to stay in Hardy-Weinberg equilibrium?

**Tip**: When solving Hardy-Weinberg problems, always make sure the genotype frequencies sum to 1 to verify your calculations.

Hardy-Weinberg equilibrium: the percentage of the homozygous recessive genotype (aa) is 36%. Using that 36%, calculate the frequency of the 'a' allele.

Learn how to calculate the frequency of the recessive allele 'a' using the Hardy-Weinberg equilibrium. Given that the homozygous recessive genotype (aa) is 36%, this step-by-step guide helps you solve for allele frequencies, covering key concepts in genetic equilibrium and population genetics. Suitable for Grades 10-12.

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