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To solve this problem, we'll use the formula for gravitational acceleration \( g \) on the surface of a planet:

\[
g = \frac{G \cdot M}{R^2}
\]

Where:
- \( G \) is the gravitational constant (it remains the same for both Earth and the exoplanet),
- \( M \) is the mass of the planet,
- \( R \) is the radius of the planet.

In this case, we're given that:
- The mass of the exoplanet is \( 1.5 \) times the mass of Earth,
- The radius of the exoplanet is \( 1.5 \) times the radius of Earth,
- The gravitational acceleration on Earth is \( g_{\text{earth}} = 9.8 \, \text{m/s}^2 \).

We want to find the gravitational acceleration on the surface of this exoplanet, \( g_{\text{exo}} \).

### Step-by-Step Calculation:
1. Let \( M_{\text{earth}} \) and \( R_{\text{earth}} \) be the mass and radius of Earth.
2. For the exoplanet, the mass is \( M_{\text{exo}} = 1.5 \cdot M_{\text{earth}} \) and the radius is \( R_{\text{exo}} = 1.5 \cdot R_{\text{earth}} \).
3. The ratio of the gravitational accelerations is:

\[
\frac{g_{\text{exo}}}{g_{\text{earth}}} = \frac{\frac{G \cdot M_{\text{exo}}}{R_{\text{exo}}^2}}{\frac{G \cdot M_{\text{earth}}}{R_{\text{earth}}^2}}
\]

Simplifying the above equation:

\[
\frac{g_{\text{exo}}}{g_{\text{earth}}} = \frac{M_{\text{exo}}}{M_{\text{earth}}} \cdot \left( \frac{R_{\text{earth}}}{R_{\text{exo}}} \right)^2
\]

Substitute the given values:

\[
\frac{g_{\text{exo}}}{g_{\text{earth}}} = \frac{1.5 \cdot M_{\text{earth}}}{M_{\text{earth}}} \cdot \left( \frac{R_{\text{earth}}}{1.5 \cdot R_{\text{earth}}} \right)^2
\]

Simplifying further:

\[
\frac{g_{\text{exo}}}{g_{\text{earth}}} = 1.5 \cdot \left( \frac{1}{1.5} \right)^2
\]

\[
\frac{g_{\text{exo}}}{g_{\text{earth}}} = 1.5 \cdot \frac{1}{2.25}
\]

\[
\frac{g_{\text{exo}}}{g_{\text{earth}}} = \frac{1.5}{2.25} = \frac{2}{3}
\]

4. Therefore:

\[
g_{\text{exo}} = \frac{2}{3} \cdot g_{\text{earth}}
\]

Substitute \( g_{\text{earth}} = 9.8 \, \text{m/s}^2 \):

\[
g_{\text{exo}} = \frac{2}{3} \cdot 9.8 \, \text{m/s}^2 = 6.53 \, \text{m/s}^2
\]

### Final Answer:
The gravitational acceleration on the exoplanet is \( \boxed{6.53 \, \text{m/s}^2} \), which corresponds to option (A).

Would you like further details, or do you have any questions? Here are some related problems you might be interested in:

1. How does the mass of an object affect gravitational acceleration?
2. If the radius of an exoplanet doubles but the mass stays constant, how would that affect gravity?
3. How would you calculate the escape velocity of an exoplanet?
4. What would happen to Earth's gravity if its radius decreased by 50% but mass remained the same?
5. How does gravitational acceleration vary with altitude?

**Tip:** Always check the relationship between mass and radius when calculating gravitational acceleration for different planets.

On another exoplanet, the mass is 1.5 times that of Earth, and the radius is 1.5 times that of Earth's radius. Calculate the acceleration due to gravity on the surface of this exoplanet. If g_earth = 9.8 m/s^2.

Learn how to calculate the acceleration due to gravity on an exoplanet where the mass is 1.5 times Earth's mass and the radius is 1.5 times Earth's radius. Step-by-step solution using Newton's Law of Universal Gravitation.

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