Math Problem Statement

Find the acceleration due to gravity on a planet with mass 1.9 cross times 10 to the power of 27 kg and radius 7.1 cross times 10 to the power of 7 m.

Information you might need:

F equals fraction numerator G M m over denominator r squared end fraction gives the magnitude of the gravitational force on an object of mass m on a planet of mass M and radius r, where G is Newton’s universal gravitational constant.

F equals m g gives the magnitude of the gravitational force on an object of mass m on a planet with acceleration due to gravity g.

G equals space 6.673 cross times 10 to the power of negative 11 end exponent space straight N space straight m squared space kg to the power of negative 2 end exponent

You do not need to include units with your answer; just give the numerical answer to an appropriate number of significant figures.

Solution

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Math Problem Analysis

Mathematical Concepts

Gravitational Force
Acceleration due to Gravity

Formulas

F = (G * M * m) / r^2
F = m * g
g = (G * M) / r^2

Theorems

Newton's Law of Universal Gravitation

Suitable Grade Level

Grades 9-12