Math Problem Statement

The image contains various quadratic function problems, including graphing equations and solving word problems related to parabolas and areas.

Solution

The image contains quadratic function problems involving graphing and word problems. Let’s break down the tasks:

  1. Graph each function (Problems 1 and 2):

    • For y=4x2y = 4x^2: A parabola opening upwards, passing through points like (0,0), (1,4), (-1,4), etc.
    • For y=3x2y = -3x^2: A parabola opening downwards, passing through points like (0,0), (1,-3), (-1,-3), etc.
  2. Problem 3:

    • A penny dropped from a height follows d=16t2+196d = -16t^2 + 196.
    • To determine the time it takes to hit the water, set d=0d = 0: 16t2+196=0-16t^2 + 196 = 0 Solving this gives t=3.5t = 3.5 seconds.
  3. Problem 4:

    • The equation A=0.25d2A = 0.25d^2 represents the area of the movie screen in terms of distance dd from the projector.
    • To estimate dd when A=7A = 7, solve 0.25d2=70.25d^2 = 7: d2=28    d=285.29d^2 = 28 \implies d = \sqrt{28} \approx 5.29
  4. Problem 5a:

    • To represent the area AA of the rectangle in terms of xx: A=x(12x)=12xx2A = x(12 - x) = 12x - x^2
  5. Problem 5b:

    • The maximum area occurs at the vertex of the parabola A=12xx2A = 12x - x^2.
    • The x-coordinate of the vertex is: x=b2a=122(1)=6x = -\frac{b}{2a} = -\frac{12}{2(-1)} = 6 So, the dimensions are 6×66 \times 6, and the maximum area is 36square inches36 \, \text{square inches}.

Let me know if you'd like detailed steps for any of these problems!

Follow-Up Questions:

  1. How do we derive the time for Problem 3 step-by-step?
  2. Can we explore how the graph of y=3x2y = -3x^2 relates to the vertex form?
  3. What are the units of the roots in Problem 3, and why is only one value used?
  4. How do we derive d2=28d^2 = 28 in Problem 4?
  5. Can the maximum area in Problem 5 be shown graphically?

Tip: Always verify the vertex formula x=b/2ax = -b/2a for maximizing or minimizing quadratic functions.

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Math Problem Analysis

Mathematical Concepts

Graphing Quadratic Functions
Vertex of a Parabola
Maximum Area
Solving Quadratic Equations

Formulas

y = ax^2 + bx + c
Vertex formula: x = -b / 2a
Area formula: A = length × width
Quadratic equation: ax^2 + bx + c = 0

Theorems

Quadratic Formula
Properties of Parabolas

Suitable Grade Level

Grades 7-10