Math Problem Statement

Given the graph of f(x) = 1/x, use transformation to graph f(x) = (4x - 1) / (2x + 1).

Solution

The problem asks you to graph f(x)=4x12x+1f(x) = \frac{4x - 1}{2x + 1} using transformations based on the graph of f(x)=1xf(x) = \frac{1}{x}. To solve this, let's break down the transformation process step by step:

Step 1: Recognizing the Base Graph

The graph of f(x)=1xf(x) = \frac{1}{x} is a hyperbola with vertical and horizontal asymptotes at x=0x = 0 and y=0y = 0, respectively. This is the reference graph.

Step 2: Analyzing the Transformation

The function we need to graph is f(x)=4x12x+1f(x) = \frac{4x - 1}{2x + 1}. This is a rational function, and transformations can be used to express how this graph relates to f(x)=1xf(x) = \frac{1}{x}.

Let's simplify the function by rewriting it:

f(x)=4x12x+1f(x) = \frac{4x - 1}{2x + 1}

Vertical Asymptote:

Set the denominator equal to zero to find the vertical asymptote:

2x+1=0    x=122x + 1 = 0 \implies x = -\frac{1}{2}

So the vertical asymptote is at x=12x = -\frac{1}{2}.

Horizontal Asymptote:

For large values of xx, the degrees of the numerator and denominator are the same, so the horizontal asymptote is determined by the ratio of the leading coefficients:

limx4x12x+1=42=2\lim_{x \to \infty} \frac{4x - 1}{2x + 1} = \frac{4}{2} = 2

Thus, the horizontal asymptote is y=2y = 2.

Step 3: Identifying Other Transformations

  • The vertical asymptote has shifted from x=0x = 0 to x=12x = -\frac{1}{2}.
  • The horizontal asymptote has shifted from y=0y = 0 to y=2y = 2.
  • The graph might have a reflection or compression/stretching, but we will also note the shape stays roughly hyperbolic due to the form of the rational function.

Step 4: Graphing the Transformation

  • Vertical asymptote: Shift the vertical asymptote from x=0x = 0 to x=12x = -\frac{1}{2}.
  • Horizontal asymptote: Shift the horizontal asymptote from y=0y = 0 to y=2y = 2.
  • Shape: The general shape will resemble a hyperbola but will approach the new asymptotes.

This completes the transformation from the basic f(x)=1xf(x) = \frac{1}{x} graph to the graph of f(x)=4x12x+1f(x) = \frac{4x - 1}{2x + 1}.

Would you like more details on any of the transformations or how to graph this step by step?

Here are some related questions:

  1. What role do vertical and horizontal asymptotes play in graphing rational functions?
  2. How do you determine the intercepts of a rational function like f(x)=4x12x+1f(x) = \frac{4x - 1}{2x + 1}?
  3. What types of transformations affect the graph of 1x\frac{1}{x}?
  4. How can you confirm that the graph of f(x)=4x12x+1f(x) = \frac{4x - 1}{2x + 1} follows the expected behavior?
  5. Can you find any points of intersection between the graph and the axes?

Tip: Always check for both vertical and horizontal asymptotes when graphing rational functions to understand their end behavior.

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Math Problem Analysis

Mathematical Concepts

Graph Transformations
Rational Functions
Asymptotes

Formulas

f(x) = 1/x (Basic graph)
f(x) = (4x - 1) / (2x + 1) (Transformed rational function)

Theorems

Vertical asymptote theorem: Set denominator to 0.
Horizontal asymptote theorem: Compare the degrees of numerator and denominator.

Suitable Grade Level

Grades 10-12