It appears that the image shows a mathematical instruction involving the phrase "Gambarlah grafik fungsi f(x) = x²". This translates to "Draw the graph of the function $f(x) = x^2$."

The graph of $f(x) = x^2$ is a parabola, which opens upwards. Here are some key features of the graph:

• Vertex: The vertex of the parabola is at $(0, 0)$, which is the lowest point since the coefficient of $x^2$ is positive.
• Axis of symmetry: The graph is symmetric about the y-axis (i.e., the vertical line $x = 0$).
• Shape: The parabola gets wider as $x$ moves away from zero.
• Intercepts:
  • The y-intercept is $f(0) = 0^2 = 0$.
  • The x-intercepts are also at $x = 0$, because $f(x) = 0$ only when $x = 0$.

Would you like a more detailed breakdown of how to sketch this graph, or any further assistance?

Here are some follow-up questions to explore:

1. How does the shape of the parabola change for other quadratic functions like $f(x) = ax^2$?
2. What is the effect of adding or subtracting a constant from $f(x) = x^2$, such as $f(x) = x^2 + 3$?
3. How does the parabola shift if the function includes a linear term, like $f(x) = x^2 + 2x$?
4. What is the domain and range of $f(x) = x^2$?
5. How do the concepts of vertex and symmetry help in sketching quadratic functions?

Tip: For any quadratic function $f(x) = ax^2 + bx + c$, the vertex can be found using $x = -\frac{b}{2a}$.