Math Problem Statement

graficar función cuadrática

Complete la tabla de valores de abajo por f(x)=x^2.

Solution

Here is the graph of the quadratic function f(x)=x2f(x) = x^2, based on the values in the table:

  • The graph is a parabola opening upwards.
  • The points are symmetric about the y-axis, with the vertex at (0,0)(0, 0).
  • Key points plotted include (4,16)(-4, 16), (3,9)(-3, 9), (2,4)(-2, 4), (1,1)(-1, 1), (0,0)(0, 0), (1,1)(1, 1), (2,4)(2, 4), (3,9)(3, 9), and (4,16)(4, 16).

Would you like any further details or explanations on this graph or the function?

Here are five related questions to explore:

  1. What are the roots of the function f(x)=x2f(x) = x^2?
  2. How do you determine the vertex of a quadratic function?
  3. What does the symmetry of the parabola tell us about the function?
  4. How does the graph of f(x)=x2+3f(x) = x^2 + 3 compare to this one?
  5. How does the graph change if the function is f(x)=x2f(x) = -x^2?

Tip: In quadratic functions, the vertex is the point of minimum or maximum value depending on whether the parabola opens upwards or downwards.

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Math Problem Analysis

Mathematical Concepts

Algebra
Quadratic Functions
Graphing Parabolas

Formulas

f(x) = x^2

Theorems

Symmetry of Parabolas
Vertex of a Quadratic Function

Suitable Grade Level

Grades 7-9