Math Problem Statement

Carlos graphs the equations y = -1/2x^2 + 4 and y = -1/2x^2 - 2x + 2 and generates the graph below. Which conclusion is supported by the graph?

Solution

Carlos graphs two quadratic equations:

  1. y=12x2+4y = -\frac{1}{2}x^2 + 4
  2. y=12x22x+2y = -\frac{1}{2}x^2 - 2x + 2

The graph shows two parabolas, and the task is to identify the conclusion supported by the graph.


Step 1: Analyze the equations

Equation 1: y=12x2+4y = -\frac{1}{2}x^2 + 4

  • This is a downward-opening parabola (since the coefficient of x2x^2 is negative).
  • The vertex form of this parabola is y=a(xh)2+ky = a(x-h)^2 + k, where (h,k)(h, k) is the vertex. For this equation:
    • a=12a = -\frac{1}{2}
    • h=0h = 0, k=4k = 4, so the vertex is (0,4)(0, 4).

Equation 2: y=12x22x+2y = -\frac{1}{2}x^2 - 2x + 2

  • This is also a downward-opening parabola.
  • To find its vertex, we rewrite it in vertex form by completing the square.

y=12x22x+2y = -\frac{1}{2}x^2 - 2x + 2 Factor out 12-\frac{1}{2} from the x2x^2 and xx terms: y=12(x2+4x)+2y = -\frac{1}{2}\left(x^2 + 4x\right) + 2 Complete the square inside the parentheses: x2+4xbecomes(x+2)24x^2 + 4x \quad \text{becomes} \quad (x+2)^2 - 4 Substitute back: y=12((x+2)24)+2y = -\frac{1}{2}\left((x+2)^2 - 4\right) + 2 Distribute 12-\frac{1}{2}: y=12(x+2)2+2+2y = -\frac{1}{2}(x+2)^2 + 2 + 2 y=12(x+2)2+4y = -\frac{1}{2}(x+2)^2 + 4 The vertex of this parabola is (2,4)(-2, 4).


Step 2: Compare the graphs

From the analysis:

  1. The first parabola has its vertex at (0,4)(0, 4).
  2. The second parabola has its vertex at (2,4)(-2, 4).

Both parabolas share the same maximum yy-value of 4, but their symmetry axes differ. The first is symmetric about x=0x = 0, while the second is symmetric about x=2x = -2.


Step 3: Supported conclusion

The graph supports the conclusion that both parabolas have the same maximum value (at y=4y = 4) but different axes of symmetry.


Would you like a deeper explanation or have further questions?
Here are five related questions to expand your understanding:

  1. How do you find the vertex of a quadratic equation in standard form?
  2. What does the coefficient of x2x^2 indicate about the shape of a parabola?
  3. How does completing the square help rewrite a quadratic equation?
  4. Why is symmetry important in understanding the graph of a parabola?
  5. What does the shared maximum value of the parabolas signify?

Tip: Always compare the vertex and the axis of symmetry to understand the differences between two quadratic graphs!

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Quadratic Equations
Graphing Parabolas
Vertex and Axis of Symmetry

Formulas

y = ax^2 + bx + c
Vertex Formula: x = -b/(2a)

Theorems

Properties of Parabolas
Symmetry of Quadratic Functions

Suitable Grade Level

Grades 9-10