Math Problem Statement

Suppose the position of an object moving horizontally after t seconds is given by the following function sequals​f(t), where s is measured in​ feet, with sgreater than0 corresponding to positions right of the origin. a. Graph the position function. b. Find and graph the velocity function. When is the object​ stationary, moving to the​ right, and moving to the​ left? c. Determine the velocity and acceleration of the object at tequals1. d. Determine the acceleration of the object when its velocity is zero. e. On what intervals is the speed​ increasing? ​f(t)equals6 t minus 2 t squared​; 0less than or equalstless than or equals7 Question content area bottom Part 1 a. Graph the position function. Choose the correct graph below. A. 0 7 -20 60 t s

A coordinate system has a horizontal t-axis labeled from 0 to 7 in increments of 1 and a vertical s-axis labeled from negative 20 to 60 in increments of 10. A parabola that opens upward has vertex (1.5, negative 4.5) and passes through the points (0, 0), (3, 0), and (7, 56). B. 0 7 0 60 t s

A coordinate system has a horizontal t-axis labeled from 0 to 7 in increments of 1 and a vertical s-axis labeled from 0 to 60 in increments of 10. From left to right, a curve is horizontal at (0, 0) and rises at an increasing rate, passing through the points (2, 4) and (7, 49). C. 0 7 -60 20 t s

A coordinate system has a horizontal t-axis labeled from 0 to 7 in increments of 1 and a vertical s-axis labeled from negative 60 to 20 in increments of 10. A parabola that opens downward has vertex (1.5, 4.5) and passes through the points (0, 0), (3, 0), and (7, negative 56). Your answer is correct.D. 0 7 -60 0 t s

A coordinate system has a horizontal t-axis labeled from 0 to 7 in increments of 1 and a vertical s-axis labeled from negative 60 to 0 in increments of 10. From left to right, a curve is horizontal at (0, 0) and falls at an increasing rate, passing through the points (2, negative 4) and (7, negative 49). Part 2 b. v left parenthesis t right parenthesisequals    enter your response here

Solution

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Math Problem Analysis

Mathematical Concepts

Differentiation
Quadratic Equations
Kinematics

Formulas

Position function: s = 6t - 2t^2
Velocity: v(t) = ds/dt = 6 - 4t
Acceleration: a(t) = dv/dt = -4

Theorems

Derivative of quadratic functions
Concept of velocity and acceleration

Suitable Grade Level

Grades 10-12