Math Problem Statement
Suppose the position of an object moving horizontally after t seconds is given by the following function sequalsf(t), where s is measured in feet, with sgreater than0 corresponding to positions right of the origin. a. Graph the position function. b. Find and graph the velocity function. When is the object stationary, moving to the right, and moving to the left? c. Determine the velocity and acceleration of the object at tequals1. d. Determine the acceleration of the object when its velocity is zero. e. On what intervals is the speed increasing? f(t)equals6 t minus 2 t squared; 0less than or equalstless than or equals7 Question content area bottom Part 1 a. Graph the position function. Choose the correct graph below. A. 0 7 -20 60 t s
A coordinate system has a horizontal t-axis labeled from 0 to 7 in increments of 1 and a vertical s-axis labeled from negative 20 to 60 in increments of 10. A parabola that opens upward has vertex (1.5, negative 4.5) and passes through the points (0, 0), (3, 0), and (7, 56). B. 0 7 0 60 t s
A coordinate system has a horizontal t-axis labeled from 0 to 7 in increments of 1 and a vertical s-axis labeled from 0 to 60 in increments of 10. From left to right, a curve is horizontal at (0, 0) and rises at an increasing rate, passing through the points (2, 4) and (7, 49). C. 0 7 -60 20 t s
A coordinate system has a horizontal t-axis labeled from 0 to 7 in increments of 1 and a vertical s-axis labeled from negative 60 to 20 in increments of 10. A parabola that opens downward has vertex (1.5, 4.5) and passes through the points (0, 0), (3, 0), and (7, negative 56). Your answer is correct.D. 0 7 -60 0 t s
A coordinate system has a horizontal t-axis labeled from 0 to 7 in increments of 1 and a vertical s-axis labeled from negative 60 to 0 in increments of 10. From left to right, a curve is horizontal at (0, 0) and falls at an increasing rate, passing through the points (2, negative 4) and (7, negative 49). Part 2 b. v left parenthesis t right parenthesisequals enter your response here
Solution
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Math Problem Analysis
Mathematical Concepts
Differentiation
Quadratic Equations
Kinematics
Formulas
Position function: s = 6t - 2t^2
Velocity: v(t) = ds/dt = 6 - 4t
Acceleration: a(t) = dv/dt = -4
Theorems
Derivative of quadratic functions
Concept of velocity and acceleration
Suitable Grade Level
Grades 10-12
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