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Here is the graph showing the path of the cannonball based on the given equation:

\[
y = x\sqrt{3} - \frac{160x^2}{297}
\]

The graph represents the trajectory of the cannonball in miles, with the horizontal axis representing distance and the vertical axis representing height.

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Here are five related questions for further exploration:
1. How can we calculate the maximum height the cannonball reaches?
2. What distance does the cannonball travel before hitting the ground?
3. How would the graph change if the angle was different, say 45 degrees?
4. Can we find the time it takes for the cannonball to reach the maximum height?
5. How does air resistance affect the path in a real-world scenario?

**Tip**: For projectile motion, the angle of elevation and the initial velocity significantly influence the shape and range of the trajectory.

Suppose a cannon is placed at the origin and elevated at an angle of 60 degrees. If the cannonball is fired with a muzzle velocity of 0.15 mile per second, it will follow the graph of y = x√3 - 160x^2/297, where distances are measured in miles. Make a graph that shows the path of the cannonball.

Learn how to graph the path of a cannonball fired at a 60-degree angle with an initial velocity of 0.15 miles per second. The graph follows the equation y = x√3 - 160x^2/297, representing projectile motion. Suitable for students in Grades 9-12.

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