Math Problem Statement

Graph the line given by y + 3 = (1/2)(x - 7).

Solution

To graph the line given by the equation:

y+3=12(x7)y + 3 = \frac{1}{2}(x - 7)

let’s start by rewriting it in slope-intercept form (y=mx+by = mx + b), which will make it easier to identify the slope and y-intercept.

Step-by-Step Solution

  1. Distribute 12\frac{1}{2} on the right side: y+3=12x72y + 3 = \frac{1}{2}x - \frac{7}{2}

  2. Isolate yy by subtracting 3 from both sides: y=12x723y = \frac{1}{2}x - \frac{7}{2} - 3

  3. Combine constants on the right: y=12x7262=12x132y = \frac{1}{2}x - \frac{7}{2} - \frac{6}{2} = \frac{1}{2}x - \frac{13}{2}

Now, the equation in slope-intercept form is: y=12x132y = \frac{1}{2}x - \frac{13}{2}

Identifying Key Points

  • Slope (mm): 12\frac{1}{2}, which means the line rises by 1 unit for every 2 units it moves to the right.
  • Y-intercept (bb): 132-\frac{13}{2} (or -6.5), so the line crosses the y-axis at (0,6.5)(0, -6.5).

Plotting the Line

  1. Start at the y-intercept point: (0,6.5)(0, -6.5).

  2. Use the slope to find another point:

    • From (0,6.5)(0, -6.5), go up 1 unit and right 2 units, reaching the point (2,5.5)(2, -5.5).
  3. Draw a straight line through these points to complete the graph.

Would you like more details on any part of this solution?


Here are some questions to explore this further:

  1. How can you convert any point-slope equation to slope-intercept form?
  2. What does the slope 12\frac{1}{2} tell us about the steepness and direction of the line?
  3. How would you find the x-intercept of this line?
  4. What other methods could be used to graph this line?
  5. How would the graph change if the slope was negative?

Tip: When graphing, using multiple points helps ensure accuracy and a straight line.

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Math Problem Analysis

Mathematical Concepts

Algebra
Linear Equations
Graphing
Slope-Intercept Form

Formulas

y = mx + b (Slope-Intercept Form)
y - y1 = m(x - x1) (Point-Slope Form)

Theorems

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Suitable Grade Level

Grades 8-10