The equation given is $y = 2x - 5$. Let me explain how to graph this step-by-step:

1. Identify the slope and y-intercept:

   • The equation is in slope-intercept form $y = mx + b$, where $m$ is the slope and $b$ is the y-intercept.
   • Here, $m = 2$ (the slope) and $b = -5$ (the y-intercept).

2. Plot the y-intercept:

   • Start by plotting the point where $y = -5$ on the y-axis. This point is $(0, -5)$.

3. Use the slope to find another point:

   • The slope $m = 2$ means "rise over run" = $\frac{2}{1}$. From the point $(0, -5)$, move up 2 units (rise) and right 1 unit (run), landing at $(1, -3)$. Plot this point.

4. Extend the line:

   • Using a ruler, draw a straight line passing through both points, extending it in both directions. Ensure the line follows the slope pattern (e.g., continuing up 2 and right 1, or down 2 and left 1).

5. Label the line:

   • Add the equation $y = 2x - 5$ near the line to identify it.

Would you like me to graph this equation step-by-step for you, or explain any of the steps in more detail?

Related Questions:

1. How do you convert an equation to slope-intercept form if not already provided?
2. What is the significance of the slope in real-world applications?
3. How do you graph horizontal or vertical lines, such as $y = c$ or $x = c$?
4. How can you check if a point lies on a given line algebraically?
5. What happens if the slope of the line is negative or fractional?

Tip: Always verify your graph by substituting a point into the original equation to ensure it satisfies the equation.