The equation given in the image is:

$4x - 5y = -20$

We are asked to plot the $x$- and $y$-intercepts and then graph the line. Let's find these intercepts.

1. To find the $x$-intercept, set $y = 0$ in the equation: $4x - 5(0) = -20 \implies 4x = -20 \implies x = -5$ So, the $x$-intercept is at $(-5, 0)$.

2. To find the $y$-intercept, set $x = 0$ in the equation: $4(0) - 5y = -20 \implies -5y = -20 \implies y = 4$ So, the $y$-intercept is at $(0, 4)$.

Now, using these points $(-5, 0)$ and $(0, 4)$, you can draw the line on the graph.

Would you like more details on how to graph it, or do you have any other questions?

Here are some relative questions for practice:

1. How would the graph change if the equation was $4x - 5y = 20$?
2. What is the slope of the line in this problem?
3. How do you convert this equation to slope-intercept form?
4. What are the coordinates of another point on this line?
5. How would you determine if a point lies on this line?

Tip: When graphing lines, always remember to label the intercepts clearly, as they are key reference points.