To graph the equation \( -2x + y = -8 \), we will first rearrange it into the slope-intercept form \( y = mx + b \), where \( m \) is the slope and \( b \) is the y-intercept.

### Step 1: Rearrange the equation

Starting with:
\[
-2x + y = -8
\]

Isolate \( y \):
\[
y = 2x - 8
\]

Now the equation is in slope-intercept form where:
- The slope \( m = 2 \)
- The y-intercept \( b = -8 \)

### Step 2: Plot the graph

1. **Start at the y-intercept**: Plot the point \( (0, -8) \) on the y-axis. This is where the line crosses the y-axis.
2. **Use the slope**: The slope is 2, meaning that for every 1 unit you move to the right (along the x-axis), the line moves 2 units up. From the point \( (0, -8) \), go 1 unit to the right (x = 1) and 2 units up to reach the point \( (1, -6) \).
3. **Draw the line**: After plotting the points, draw a straight line through them.

The line will be upward sloping since the slope is positive.

Would you like me to provide more details or have any further questions?

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### Related Questions:
1. How would the graph change if the equation was \( -2x + y = 8 \)?
2. How do you find the x-intercept of a line given its equation?
3. What does the slope of the line represent in real-world terms?
4. How would the graph look if the slope was negative?
5. How can you graph a line using two points instead of slope-intercept form?

**Tip**: Always check the slope and intercept values first when graphing a line—it makes the process much quicker!

Learn how to graph the line for the equation -2x + y = -8. The solution includes step-by-step instructions on converting to slope-intercept form and plotting the graph using the slope and y-intercept. This is suitable for students in Grades 8-9.

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