The equation of the line given is $y = -x - 2$, which is in slope-intercept form $y = mx + b$. Here's the breakdown:

• Slope (m): The coefficient of $x$ is $-1$, so the slope is $-1$. This means for every 1 unit you move to the right on the $x$-axis, you move 1 unit down on the $y$-axis.
• Y-intercept (b): The constant $-2$ is the y-intercept, meaning the line crosses the $y$-axis at $(0, -2)$.

Steps to graph the line:

1. Plot the y-intercept at $(0, -2)$.
2. Use the slope to find another point. Since the slope is $-1$, from $(0, -2)$, move 1 unit to the right and 1 unit down to get to $(1, -3)$.
3. Repeat this to plot a few more points, e.g., $(2, -4)$, $(-1, -1)$, etc.
4. Draw the line through these points.

Would you like more details on graphing, or should I help with anything else?

Here are some related questions:

1. How do you determine the slope of a line from an equation?
2. What is the significance of the y-intercept in a linear equation?
3. How does changing the slope affect the angle of the line on the graph?
4. What is the equation of a line parallel to $y = -x - 2$?
5. How would you graph a line with a positive slope instead of a negative one?

Tip: The slope indicates how steep the line is. A larger absolute value of the slope results in a steeper line!