Math Problem Statement

graph each hyberbola by hand give the domain and range (x^(2))/(16 ) - (y^(2))/(9) =1

Solution

To graph the hyperbola given by the equation:

x216y29=1\frac{x^2}{16} - \frac{y^2}{9} = 1

we need to follow these steps:

  1. Identify the center, vertices, and asymptotes:

    • This hyperbola is centered at the origin (0,0)(0,0) because there are no hh and kk values in the equation.
    • The equation is in the standard form x2a2y2b2=1\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1, where a2=16a^2 = 16 and b2=9b^2 = 9. Thus, a=4a = 4 and b=3b = 3.
  2. Vertices:

    • For hyperbolas of the form x2a2y2b2=1\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1, the vertices are at (±a,0)(\pm a, 0).
    • Therefore, the vertices are (±4,0)(\pm 4, 0), which are (4,0)(4, 0) and (4,0)(-4, 0).
  3. Asymptotes:

    • The equations of the asymptotes for hyperbolas in this form are y=±baxy = \pm \frac{b}{a} x.
    • Substituting a=4a = 4 and b=3b = 3, the asymptote equations are y=±34xy = \pm \frac{3}{4} x.
  4. Graphing the Hyperbola:

    • Draw the center at the origin (0,0)(0,0).
    • Plot the vertices at (4,0)(4,0) and (4,0)(-4,0).
    • Draw the asymptotes y=34xy = \frac{3}{4}x and y=34xy = -\frac{3}{4}x. These lines pass through the origin and have slopes of ±34\pm \frac{3}{4}.
    • Sketch the hyperbola opening left and right, approaching but never touching the asymptotes.
  5. Domain and Range:

    • For the hyperbola x216y29=1\frac{x^2}{16} - \frac{y^2}{9} = 1:
      • The domain (set of all possible xx-values) is x(,4][4,)x \in (-\infty, -4] \cup [4, \infty).
      • The range (set of all possible yy-values) is y(,)y \in (-\infty, \infty).

Here's the graph of the hyperbola:

  1. Draw a set of coordinate axes.
  2. Mark the center at (0,0)(0,0).
  3. Plot the vertices at (4,0)(4,0) and (4,0)(-4,0).
  4. Draw the asymptotes: y=34xy = \frac{3}{4}x and y=34xy = -\frac{3}{4}x.
  5. Sketch the branches of the hyperbola, opening to the left and right, approaching the asymptotes.

Would you like more details or have any questions?

Here are some related questions:

  1. How do you derive the standard form of a hyperbola from its general equation?
  2. What are the differences between the equations of horizontal and vertical hyperbolas?
  3. How do you determine the foci of a hyperbola?
  4. How do you find the lengths of the transverse and conjugate axes of a hyperbola?
  5. How do you determine the eccentricity of a hyperbola?
  6. How do the asymptotes help in sketching the graph of a hyperbola?
  7. How can you verify if a given equation represents a hyperbola?
  8. What are the properties of hyperbolas that differentiate them from other conic sections?

Tip: When graphing a hyperbola, always start by identifying the center, vertices, and asymptotes. These key elements guide the accurate sketching of the hyperbola's shape.

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Math Problem Analysis

Mathematical Concepts

Hyperbolas
Conic Sections

Formulas

Standard form of a hyperbola: \(\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1\)
Equations of asymptotes for hyperbolas

Theorems

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Suitable Grade Level

Grades 11-12