The graph of the quadratic function $y = x^2 + x - 2$ has been plotted. The parabola opens upwards, and its vertex is located at $(-0.5, -2.25)$. The function crosses the x-axis at two points (the roots), which are the solutions to the equation $x^2 + x - 2 = 0$.

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Here are five related questions to explore:

1. How do you find the roots of the quadratic function $y = x^2 + x - 2$?
2. What is the axis of symmetry for the quadratic function?
3. How do you determine if the parabola opens upwards or downwards?
4. Can you express the quadratic function in vertex form?
5. What happens to the graph if you change the coefficients in the quadratic function?

Tip: The vertex of a quadratic function $y = ax^2 + bx + c$ can be found using the formula $x = -\frac{b}{2a}$.