The system of linear inequalities given is:

$-2 \leq x < 3$

This inequality represents all values of $x$ that are between $-2$ and $3$, including $-2$ but not including $3$. To graph this on a number line:

1. Place a closed circle at $-2$ to indicate that $-2$ is included in the solution set.
2. Place an open circle at $3$ to indicate that $3$ is not included in the solution set.
3. Shade the region between $-2$ and $3$ to show all the values $x$ that satisfy the inequality.

This visually demonstrates that any $x$ in the interval $[-2, 3)$ is a solution.

Would you like further details or have any questions?

Here are 5 related questions to expand on this information:

1. How would the graph change if the inequality were $-2 < x \leq 3$?
2. What is the difference between an open and a closed circle on a number line?
3. How would you write the interval notation for this solution set?
4. How can this inequality be represented on a coordinate plane instead of a number line?
5. What would the graph look like if the inequality were $x > -2$ and $x \leq 3$?

Tip: When graphing inequalities, remember that a closed circle means the endpoint is included (≤ or ≥), while an open circle means it is not included (< or >).