The task requires filling in the function table based on the equation $f(x) = 2x - 7$, and then plotting the points on the graph.

Step 1: Calculate $f(x) = 2x - 7$ for each value of $x$:

• When $x = 0$: $f(0) = 2(0) - 7 = -7$
• When $x = 1$: $f(1) = 2(1) - 7 = -5$
• When $x = 2$: $f(2) = 2(2) - 7 = -3$
• When $x = 3$: $f(3) = 2(3) - 7 = -1$
• When $x = 4$: $f(4) = 2(4) - 7 = 1$

Step 2: The table values are:

Step 3: Plot these points on the graph:

• Plot (0, -7)
• Plot (1, -5)
• Plot (2, -3)
• Plot (3, -1)
• Plot (4, 1)

This forms a straight line since $f(x) = 2x - 7$ is a linear function.

Would you like further clarification on plotting the points or understanding the function? Here are some related questions:

1. What is the slope and y-intercept of the function $f(x) = 2x - 7$?
2. How does changing the slope affect the graph of the line?
3. Can you find the x-intercept of this line?
4. What happens if we change the equation to $f(x) = -2x + 7$?
5. How would you plot points for a quadratic function instead of a linear one?

Tip: The slope of a line tells you how steep it is; the larger the slope, the steeper the line.