The equation given is $y = 4x - 3$, which is in slope-intercept form $y = mx + b$, where $m = 4$ is the slope and $b = -3$ is the y-intercept.

The first step in graphing this linear equation is to plot the y-intercept. The y-intercept is the point where the line crosses the y-axis, which happens when $x = 0$.

From the equation $y = 4(0) - 3$, we get: $y = -3$ Thus, the point to plot is $(0, -3)$.

The correct values to complete the sentence are:
Plot the point $(0, -3)$.

Would you like more details on how to graph the rest of the equation? Here are five questions to further your understanding:

1. What does the slope $m = 4$ represent in the graph of this equation?
2. How can you find another point on the line using the slope?
3. Why is the y-intercept important for graphing linear equations?
4. What would the graph look like if the slope were negative?
5. How would changing the y-intercept affect the position of the graph?

Tip: When graphing, always start by plotting the y-intercept, then use the slope to find additional points!