The equation shown above the graph is $y - 4x = 1$, which can be rewritten as $y = 4x + 1$ to represent the line in slope-intercept form $y = mx + b$, where $m$ is the slope and $b$ is the y-intercept.

Steps to graph this line:

1. Identify the y-intercept (b):

   • In the equation $y = 4x + 1$, the y-intercept is $b = 1$, which means the line crosses the y-axis at $(0, 1)$.

2. Identify the slope (m):

   • The slope is $m = 4$, which means for every 1 unit increase in $x$, $y$ increases by 4 units.

3. Plot the points:

   • Start by plotting the point $(0, 1)$ on the y-axis.
   • From this point, use the slope to find another point. Move 1 unit to the right (increase $x$ by 1) and move 4 units up (increase $y$ by 4). This gives the point $(1, 5)$.
   • You can also move in the opposite direction: move 1 unit to the left (decrease $x$ by 1) and move 4 units down (decrease $y$ by 4). This gives the point $(-1, -3)$.

4. Draw the line:

   • Connect these points to form a straight line.

Would you like me to generate the graph based on these points and the equation, or provide further details?

Here are 5 related questions to expand your understanding:

1. What does the slope of 4 tell us about the steepness of the line?
2. How would the graph change if the slope were negative?
3. What would the y-intercept be if the equation were $y - 4x = -2$?
4. How can we determine the x-intercept from this equation?
5. How does the equation $y = mx + b$ relate to real-life scenarios?

Tip: In slope-intercept form, the slope $m$ controls the steepness of the line, while the y-intercept $b$ determines where the line crosses the y-axis.