Math Problem Statement
Sketch the graph of a function that has a hole/removable discontinuity at x = 1, a jump discontinuity at x = 2 and a vertical asymptote/infinite discontinuity at x = 3. Copyright ©2024 UConn Department of Mathematics. All rights reserved. Page 4
Solution
To sketch a function with the given discontinuities, follow these conditions:
-
Hole (removable discontinuity) at :
- The function is defined everywhere except at .
- There is a point missing (a hole) at .
- The function may have a limit at , but it does not take that value.
-
Jump discontinuity at :
- The left-hand limit () and right-hand limit () exist but are not equal.
- This creates a sudden jump in the graph at .
-
Vertical asymptote at (infinite discontinuity):
- The function approaches infinity ( or ) as approaches 3.
- The graph gets arbitrarily large or small near .
Possible Function Definition:
A function that satisfies these conditions could be:
\begin{cases} \frac{x^2 - 1}{x - 1}, & x \neq 1, x < 2 \quad \text{(hole at $$x = 1$$)} \\ 2, & x = 1 \quad \text{(hole, value not included in function)} \\ 3, & x = 2^- \quad \text{(left-hand limit at $$x = 2$$)} \\ 1, & x = 2^+ \quad \text{(right-hand limit at $$x = 2$$)} \\ \frac{1}{x - 3}, & x > 2, x \neq 3 \quad \text{(vertical asymptote at $$x = 3$$)} \end{cases}$$ ### Sketching the Graph: - **At $$x = 1$$,** draw a small open circle where the hole is. - **At $$x = 2$$,** show a jump by plotting different points for the left and right limits. - **At $$x = 3$$,** show the function approaching positive or negative infinity on either side of the vertical asymptote. Would you like a visual sketch of this function? --- ### Related Questions: 1. What is the formal definition of removable and jump discontinuities? 2. How do you find vertical asymptotes of a rational function? 3. What are the differences between discontinuities in piecewise functions and rational functions? 4. Can a function have more than one removable discontinuity? 5. How do limits help classify discontinuities? **Tip:** A removable discontinuity occurs when a function is undefined at a point, but the limit exists. If you redefine the function at that point, continuity can be restored.Ask a new question for Free
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Math Problem Analysis
Mathematical Concepts
Calculus
Discontinuities
Piecewise Functions
Asymptotes
Formulas
f(x) = (x^2 - 1)/(x - 1)
f(x) = 1/(x - 3)
Theorems
Limit Theorem
Definition of Continuity
Asymptote Behavior
Suitable Grade Level
Grades 11-12
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