Math Problem Statement

A woman walks from her house to her neighbor’s house, and back to her house. Her position has been logged by an app on her phone every 60 seconds. Here is a table of her motion data.

Graph her walking data in a Displacement vs. Time graph on a separate piece of graph paper.  

Calculate the average velocity at 3 different time blocks during the trip using the graph you made. 

Distance from House (m)

Time (s)

0

0

84

60

160

120

245

180

154

240

90

300

6

360

Solution

To address the problem, here’s the step-by-step process you should follow:

1. Plot the Displacement vs. Time Graph:

  • X-axis: Time (in seconds) ranging from 0 to 360 seconds.
  • Y-axis: Displacement from the house (in meters) ranging from 0 to 245 meters.

Points to plot:

  • (0, 0)
  • (60, 84)
  • (120, 160)
  • (180, 245)
  • (240, 154)
  • (300, 90)
  • (360, 6)

2. Calculate the Average Velocity in 3 Different Time Blocks:

Average velocity in a given time block is calculated using the formula:

Average Velocity=Change in DisplacementChange in Time\text{Average Velocity} = \frac{\text{Change in Displacement}}{\text{Change in Time}}

Let's calculate the average velocity for three time blocks:

Time Block 1: From 0s to 180s

  • Initial displacement: 0 meters
  • Final displacement: 245 meters
  • Change in displacement: 2450=245245 - 0 = 245 meters
  • Change in time: 1800=180180 - 0 = 180 seconds

Average Velocity=245 m180 s1.36 m/s\text{Average Velocity} = \frac{245 \text{ m}}{180 \text{ s}} \approx 1.36 \text{ m/s}

Time Block 2: From 180s to 300s

  • Initial displacement: 245 meters
  • Final displacement: 90 meters
  • Change in displacement: 90245=15590 - 245 = -155 meters (indicating a return towards the house)
  • Change in time: 300180=120300 - 180 = 120 seconds

Average Velocity=155 m120 s1.29 m/s\text{Average Velocity} = \frac{-155 \text{ m}}{120 \text{ s}} \approx -1.29 \text{ m/s}

Time Block 3: From 300s to 360s

  • Initial displacement: 90 meters
  • Final displacement: 6 meters
  • Change in displacement: 690=846 - 90 = -84 meters
  • Change in time: 360300=60360 - 300 = 60 seconds

Average Velocity=84 m60 s=1.4 m/s\text{Average Velocity} = \frac{-84 \text{ m}}{60 \text{ s}} = -1.4 \text{ m/s}

Summary of Average Velocities:

  1. 0s to 180s: 1.36 m/s (away from the house)
  2. 180s to 300s: -1.29 m/s (toward the house)
  3. 300s to 360s: -1.4 m/s (toward the house)

Would you like further clarification or any additional help?

Here are 5 related questions:

  1. How would you describe the woman’s journey based on the displacement vs. time graph?
  2. What does a negative average velocity signify in this context?
  3. How would the graph look if the woman had walked at a constant velocity?
  4. Can you determine the maximum speed during the trip from the data?
  5. How would the displacement vs. time graph differ from a distance vs. time graph?

Tip: When plotting a displacement vs. time graph, pay close attention to the slope of the line. The slope directly represents the velocity.

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Math Problem Analysis

Mathematical Concepts

Physics
Kinematics
Average Velocity

Formulas

Average Velocity formula: \( \text{Average Velocity} = \frac{\text{Change in Displacement}}{\text{Change in Time}} \)

Theorems

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Suitable Grade Level

Grades 9-12