Math Problem Statement

graph (y+1)^3-2 and find the domain and give the points

Solution

To graph the function (y+1)32(y + 1)^3 - 2 and determine its domain, let's first analyze the function step by step.

1. Equation Rearrangement:

We have the equation: (x=(y+1)32)(x = (y + 1)^3 - 2) This can be viewed as an equation in terms of yy, meaning xx is dependent on yy. It's an inverted cubic function, and the variable yy is inside the transformation (y+1)(y + 1), while the entire expression is shifted down by 2.

2. Domain:

The domain refers to the set of all possible values of yy for which the function is defined. Since this is a cubic function, there are no restrictions on yy (i.e., it can take any real value). Thus, the domain is: Domain:R (all real numbers)\text{Domain}: \mathbb{R} \text{ (all real numbers)}

3. Points:

To find the key points, let's pick several yy-values and calculate corresponding xx-values:

  • When y=0y = 0: x=(0+1)32=132=12=1x = (0 + 1)^3 - 2 = 1^3 - 2 = 1 - 2 = -1 Point: (x,y)=(1,0)(x, y) = (-1, 0)

  • When y=1y = -1: x=(1+1)32=032=2x = (-1 + 1)^3 - 2 = 0^3 - 2 = -2 Point: (x,y)=(2,1)(x, y) = (-2, -1)

  • When y=1y = 1: x=(1+1)32=232=82=6x = (1 + 1)^3 - 2 = 2^3 - 2 = 8 - 2 = 6 Point: (x,y)=(6,1)(x, y) = (6, 1)

  • When y=2y = -2: x=(2+1)32=(1)32=12=3x = (-2 + 1)^3 - 2 = (-1)^3 - 2 = -1 - 2 = -3 Point: (x,y)=(3,2)(x, y) = (-3, -2)

  • When y=2y = 2: x=(2+1)32=332=272=25x = (2 + 1)^3 - 2 = 3^3 - 2 = 27 - 2 = 25 Point: (x,y)=(25,2)(x, y) = (25, 2)

4. Graph Shape:

The graph of x=(y+1)32x = (y + 1)^3 - 2 is a cubic curve, flipped so that it's horizontal. The shape of a cubic function has a smooth curve with one point of inflection, and in this case, it's shifted and stretched based on the transformations applied.

5. Summary:

  • Domain: All real numbers, y(,)y \in (-\infty, \infty)
  • Key points:
    • (1,0)(-1, 0)
    • (2,1)(-2, -1)
    • (6,1)(6, 1)
    • (3,2)(-3, -2)
    • (25,2)(25, 2)

Let me know if you want me to generate the graph!

Would you like any further details? Here are 5 related questions to expand on this:

  1. How would the graph look if you added another transformation, such as multiplying by a constant?
  2. What would happen to the points if the cubic function was reflected?
  3. Can you describe the behavior of cubic functions in general?
  4. How can we use calculus to find the turning point or inflection of a cubic function?
  5. What is the range of this cubic function?

Tip: When graphing functions, always note any transformations like shifts, reflections, and stretching/compressing to understand how they affect the shape of the graph.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Algebra
Cubic Functions
Graphing
Domain and Range

Formulas

x = (y + 1)^3 - 2

Theorems

Cubic function properties
Domain of functions

Suitable Grade Level

Grades 9-11