Math Problem Statement

The graph of a function g(x) is given. Find the following: (i) Domain of g (in interval notation) (ii) Range of g (in interval notation) (iii) g(-2), g(0), g(2) (iv) All values of x such that g(x) = -4 (v) Intervals of increase (vi) Intervals of decrease (vii) Any local maximum and local minimum values.

Solution

Let's analyze the graph and answer each part of the question.

(i) Domain of gg (in interval notation)

The domain represents the set of all possible xx-values for which the function is defined.

  • From the graph, the function seems to extend indefinitely to the left and right, covering all xx-values except there is a gap at x=3x = 3 where the function is undefined.

  • Domain: (,3)(3,)(-\infty, 3) \cup (3, \infty)

(ii) Range of gg (in interval notation)

The range represents the set of all possible yy-values that the function can take.

  • The graph has yy-values from 4-4 (the lowest point) up to 4 (the highest point).

  • Range: [4,4][-4, 4]

(iii) g(2)g(-2), g(0)g(0), g(2)g(2)

From the graph:

  • g(2)=3g(-2) = -3 (at x=2x = -2, the yy-value is 3-3).
  • g(0)=2g(0) = -2 (at x=0x = 0, the yy-value is 2-2).
  • g(2)=0g(2) = 0 (at x=2x = 2, the yy-value is 00).

So,

  • g(2)=3g(-2) = -3
  • g(0)=2g(0) = -2
  • g(2)=0g(2) = 0

(iv) All values of xx such that g(x)=4g(x) = -4

To find where g(x)=4g(x) = -4, we look at where the graph touches y=4y = -4.

  • From the graph, g(x)=4g(x) = -4 at x=1x = 1.

So, x=1x = 1.

(v) Intervals of increase

The function is increasing when the graph moves upward as xx increases.

  • From x=1x = 1 to x=3x = 3
  • From x=3x = 3 to \infty

So, the intervals of increase are:

  • (1,3)(1, 3) and (3,)(3, \infty).

(vi) Intervals of decrease

The function is decreasing when the graph moves downward as xx increases.

  • From -\infty to x=1x = 1

So, the interval of decrease is:

  • (,1)(-\infty, 1)

(vii) Any local maximum and local minimum values

  • Local minimum: Occurs at x=1x = 1, where g(1)=4g(1) = -4.
  • Local maximum: Occurs at x=3x = 3, where g(3)=0g(3) = 0 (even though there's a hole, it's the local maximum of the continuous part).

Would you like further details on any part of the solution? Here are 5 follow-up questions to expand your understanding:

  1. How would the domain change if the hole at x=3x = 3 were filled?
  2. What would be the domain if the function were not continuous at x=1x = 1?
  3. How do you identify intervals of increase and decrease from a graph?
  4. What happens to the range if the graph is shifted vertically?
  5. How do you find the local maxima and minima of a function from its graph?

Tip: Always check for discontinuities (like holes or jumps) when determining the domain of a function.

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Math Problem Analysis

Mathematical Concepts

Functions
Domain and Range
Increasing and Decreasing Intervals
Local Maxima and Minima

Formulas

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Theorems

Graph Analysis

Suitable Grade Level

Grades 9-12