Math Problem Statement

Use the graph to determine a. the​ function's domain; b. the​ function's range; c. the​ x-intercepts, if​ any; d. the​ y-intercept, if​ any; and e. the missing function​ values, indicated by question​ marks, below. f left parenthesis negative 2 right parenthesisf(−2)equals=​?   f left parenthesis 2 right parenthesisf(2)equals=​?

Use the graph to determine a. the​ function's domain; b. the​ function's range; c. the​ x-intercepts, if​ any; d. the​ y-intercept, if​ any; and e. the missing function​ values, indicated by question​ marks, below. f(−2)=​? f(2)=​?

Solution

Let's analyze the provided graph and determine the requested information:

a. Domain of the function

The domain of a function is the set of all possible xx-values for which the function is defined. In this case, the curve extends from the left side of the graph at x=5x = -5 to the right side at x=5x = 5, so the domain is:

Domain=[5,5]\text{Domain} = [-5, 5]

b. Range of the function

The range is the set of all possible yy-values that the function attains. The highest point on the graph occurs just below y=3y = 3, and the lowest point occurs at y=5y = -5. Therefore, the range is:

Range=[5,3)\text{Range} = [-5, 3)

(Note: The parenthesis for 3 indicates that the graph does not reach y=3y = 3, only very close to it.)

c. xx-intercepts

The xx-intercepts are the points where the graph crosses the xx-axis. From the graph, we can see that the curve crosses the xx-axis at two points: x=4x = -4 and x=2x = 2. Thus, the xx-intercepts are:

x-intercepts=(4,0)and(2,0)x\text{-intercepts} = (-4, 0) \quad \text{and} \quad (2, 0)

d. yy-intercept

The yy-intercept is the point where the graph crosses the yy-axis. The graph crosses the yy-axis at y=3y = -3, so the yy-intercept is:

y-intercept=(0,3)y\text{-intercept} = (0, -3)

e. Missing function values

  • f(2)f(-2): To find f(2)f(-2), we look at the point on the graph where x=2x = -2. From the graph, it seems the corresponding yy-value is around 2. Thus,

    f(2)=2f(-2) = 2

  • f(2)f(2): Since x=2x = 2 is an xx-intercept, the function value at x=2x = 2 is zero:

    f(2)=0f(2) = 0

Summary of Results:

  • Domain: [5,5][-5, 5]
  • Range: [5,3)[-5, 3)
  • xx-intercepts: (4,0)(-4, 0) and (2,0)(2, 0)
  • yy-intercept: (0,3)(0, -3)
  • f(2)=2f(-2) = 2
  • f(2)=0f(2) = 0

Would you like to go into more detail on any part? Here are some related questions:

  1. How can the function's symmetry be described based on the graph?
  2. What type of function might this be based on its shape (e.g., polynomial, quadratic)?
  3. How could the graph be transformed (shifted or scaled) to match a different function?
  4. What are the possible real-world applications of interpreting such functions?
  5. How does the domain and range change if the graph extends beyond x=5x = 5 or x=5x = -5?

Tip: When interpreting graphs, always check where the function intersects the axes, as this provides crucial information for solving equations involving roots and intercepts.

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Math Problem Analysis

Mathematical Concepts

Function Analysis
Domain and Range
Intercepts
Graph Interpretation

Formulas

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Theorems

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Suitable Grade Level

Grades 9-12