Math Problem Statement

Multiple-choice math problems involving interior angles of polygons, trapezoids, and pentagons, along with solving for unknown angles in given shapes.

Solution

Let's go through the questions step by step.

24. What is the measure of each interior angle of a regular decagon?

For a regular polygon, the formula for the measure of each interior angle is:

Interior Angle=(n2)×180n\text{Interior Angle} = \frac{(n-2) \times 180^\circ}{n}

For a decagon (n = 10):

Interior Angle=(102)×18010=8×18010=144\text{Interior Angle} = \frac{(10-2) \times 180^\circ}{10} = \frac{8 \times 180^\circ}{10} = 144^\circ

Thus, the correct answer is c. 144°.

25. Which is NOT a possible angle measure of a regular polygon?

Again, using the formula for the interior angle of a regular polygon, we check which of the given options cannot be the angle for a polygon:

We know the interior angle is:

Interior Angle=(n2)×180n\text{Interior Angle} = \frac{(n-2) \times 180^\circ}{n}

Trying some values:

  • 108108^\circ corresponds to an n = 5 (Pentagon).
  • 128.6128.6^\circ corresponds to n = 7.
  • 135135^\circ corresponds to n = 8.

But 125125^\circ does not correspond to a whole number value for n, so b. 125° is not possible.

26. The sum of the measures of the interior angles of a polygon is 1620°. How many sides does the polygon have?

The sum of the interior angles of a polygon is given by:

Sum of Interior Angles=(n2)×180\text{Sum of Interior Angles} = (n-2) \times 180^\circ

Setting this equal to 1620°:

(n2)×180=1620(n-2) \times 180 = 1620

Solving for nn:

n2=1620180=9    n=11n-2 = \frac{1620}{180} = 9 \implies n = 11

Thus, the polygon has 11 sides (c. 11).

27. Calculate the measure of X\angle X in this isosceles trapezoid.

In an isosceles trapezoid, the two base angles are equal, and the sum of the adjacent angles is 180°. Given one angle as 62°, the adjacent angle XX is:

X=18062=118\angle X = 180^\circ - 62^\circ = 118^\circ

Thus, the correct answer is d. 118°.

28. Calculate the measure of X\angle X in the pentagon below.

The sum of the angles in a pentagon is:

Sum of Angles=(52)×180=540\text{Sum of Angles} = (5-2) \times 180^\circ = 540^\circ

Summing the given angles: 110+82+105+153=450110^\circ + 82^\circ + 105^\circ + 153^\circ = 450^\circ. Therefore:

X=540450=90\angle X = 540^\circ - 450^\circ = 90^\circ

None of the choices match, suggesting either a mistake in the question or the figure, but based on calculation, the correct answer should be 90°.


Would you like any details for these explanations? Here are five related questions:

  1. How do you derive the formula for the interior angles of any polygon?
  2. What is the sum of the interior angles of a hexagon?
  3. How do you find the exterior angle of a regular polygon?
  4. What is the interior angle of a regular 15-sided polygon?
  5. If a polygon has an interior angle sum of 1440°, how many sides does it have?

Tip: For regular polygons, the measure of each exterior angle is easy to calculate: just divide 360° by the number of sides!

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Math Problem Analysis

Mathematical Concepts

Geometry
Polygons
Interior and Exterior Angles
Angle Relationships in Isosceles Trapezoids and Pentagons

Formulas

Interior angle of a regular polygon: (n-2) * 180° / n
Sum of interior angles of a polygon: (n-2) * 180°
Angle sum in a trapezoid: Adjacent angles sum to 180°

Theorems

Polygon Interior Angle Theorem
Trapezoid Angle Theorem
Sum of Interior Angles Theorem for Polygons

Suitable Grade Level

Grades 7-10