Math Problem Statement

Answer the questions

Geometry quiz on angle measures and relationships, involving angle classification, vertex identification, and solving for unknown angles using algebraic expressions.

Solution

I can now see the image. Let's work through the problems one by one:

Questions 1-7 (based on the diagram in the top half):

  1. Name the sides of ∠4.

    • The sides of ∠4 are rays DF and DE.
  2. Name the vertex of ∠2.

    • The vertex of ∠2 is point D.
  3. Give another name for ∠3.

    • Another name for ∠3 is ∠CDF.
  4. Classify ∠5.

    • ∠5 is a right angle (since it is marked as 90°).
  5. Classify ∠CDE.

    • ∠CDE is a straight angle (since it forms a straight line).
  6. If m∠2 = 42° and m∠1 = 117°, find m∠CDF.

    • Since ∠1 and ∠CDF form a straight angle, mCDF=180m1m\angle CDF = 180^\circ - m\angle 1. mCDF=180117=63m\angle CDF = 180^\circ - 117^\circ = 63^\circ Thus, mCDF=63m\angle CDF = 63^\circ.
  7. If m∠3 = 73°, find m∠FDE.

    • Since ∠3 and ∠FDE form a straight line, we can find: mFDE=180m3=18073=107m\angle FDE = 180^\circ - m\angle 3 = 180^\circ - 73^\circ = 107^\circ Thus, mFDE=107m\angle FDE = 107^\circ.

Questions 8-10 (based on the diagram in the bottom half):

  1. If m∠ZABF = (7x + 20)°, m∠FBC = (2x - 5)°, and m∠ABC = 159°, find the value of x.

    • The sum of the angles around point B must equal 180°, so: (7x+20)+(2x5)+159=180(7x + 20) + (2x - 5) + 159 = 180 Simplifying: 9x+174=1809x + 174 = 180 Subtract 174 from both sides: 9x=69x = 6 Solving for xx: x=69=23x = \frac{6}{9} = \frac{2}{3}
  2. If m∠DBC = (12x - 3)°, m∠DBE = (5x + 12)°, and m∠EBC = (3x + 13)°, find m∠EBC.

    • The sum of the angles around point B should equal 180°, so: (12x3)+(5x+12)+(3x+13)=180(12x - 3) + (5x + 12) + (3x + 13) = 180 Simplifying: 20x+22=18020x + 22 = 180 Subtract 22 from both sides: 20x=15820x = 158 Solving for xx: x=15820=7.9x = \frac{158}{20} = 7.9 Now, find mEBCm\angle EBC: mEBC=3x+13=3(7.9)+13=23.7+13=36.7m\angle EBC = 3x + 13 = 3(7.9) + 13 = 23.7 + 13 = 36.7^\circ
  3. If m∠FBC = (10x - 9)°, m∠CBE = (4x + 15)°, find m∠FBE.

  • The sum of the two angles must equal 180° (since they form a straight line): (10x9)+(4x+15)=180(10x - 9) + (4x + 15) = 180 Simplifying: 14x+6=18014x + 6 = 180 Subtract 6 from both sides: 14x=17414x = 174 Solving for xx: x=17414=12.43x = \frac{174}{14} = 12.43 Now, find mFBEm\angle FBE: mFBE=180m\angle FBE = 180^\circ

Let me know if you'd like further details or explanations.

Here are 5 related questions to expand your understanding:

  1. What is a complementary angle and how does it relate to this quiz?
  2. How can we classify angles based on their measurements?
  3. How would you solve for unknown angles in a triangle?
  4. What are linear pairs of angles, and where do they appear in the diagrams?
  5. How can bisectors be used to find unknown angle measures?

Tip: When solving for angles, always check if angles form a straight line (180°) or a right angle (90°) for easy calculations.

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Math Problem Analysis

Mathematical Concepts

Geometry
Angle Relationships
Algebra

Formulas

Sum of angles on a straight line = 180°
Sum of angles in a triangle = 180°

Theorems

Linear Pair Theorem
Angle Addition Postulate
Bisector Theorem

Suitable Grade Level

Grades 9-10