Math Problem Statement

Solve the geometry and ratio problems involving areas of triangles, parallelograms, and ratios of sides given in the image.

Solution

Let's solve the problems from the image you provided.

1. Area of Striped Parts in the Rectangle (First Image):

You are asked to find the area of the striped region in the combined rectangle structure.

  • The total area of the outer rectangle is: Area of outer rectangle=8cm×12cm=96cm2\text{Area of outer rectangle} = 8 \, \text{cm} \times 12 \, \text{cm} = 96 \, \text{cm}^2

  • The area of the lower striped rectangle: Area of lower rectangle=2cm×8cm=16cm2\text{Area of lower rectangle} = 2 \, \text{cm} \times 8 \, \text{cm} = 16 \, \text{cm}^2

  • The area of the upper triangle: Area of triangle=12×6cm×4cm=12cm2\text{Area of triangle} = \frac{1}{2} \times 6 \, \text{cm} \times 4 \, \text{cm} = 12 \, \text{cm}^2

Thus, the total striped area is the sum: Striped area=16cm2+12cm2=28cm2\text{Striped area} = 16 \, \text{cm}^2 + 12 \, \text{cm}^2 = 28 \, \text{cm}^2


2. Problem 9: Area of Striped Triangle (ABCD with Area of 20 cm²)

You are given a rectangle with an area of 20 cm² and need to find the area of the striped triangle.

  • The total area of the rectangle is 20cm220 \, \text{cm}^2.
  • The base AEAE is half of ABAB, meaning AE=AB2AE = \frac{AB}{2}.
  • AFAF is half of AEAE, implying AF=AE2=AB4AF = \frac{AE}{2} = \frac{AB}{4}.

Since the area of a triangle is given by 12×base×height\frac{1}{2} \times \text{base} \times \text{height}, and based on the proportional division, the area of the triangle will be 5 cm², which corresponds to Option C.


3. Problem 10: Area Ratio of Parallelogram ABCD

You are asked to find the ratio of the areas of triangles ABCMABCM and ANDAND, where 3MD=2MC3MD = 2MC.

This implies the area of triangle ABCMABCM is proportional to its height, and ANDAND's area will depend on the division of triangle heights. By simplifying, the correct ratio is found to be 7:8, which is Option C.


4. Problem 11: Finding Ratio ADDC\frac{AD}{DC}

In the triangle ABCABC with sides given as AB=5AB = 5, BD=5BD = 5, BC=7BC = 7, and AC=9AC = 9, you need to find the ratio ADDC\frac{AD}{DC}.

By applying the triangle proportionality theorem or similar triangles concept, you get: ADDC=187\frac{AD}{DC} = \frac{18}{7} Thus, the answer is Option C.


5. Problem 12: Smallest Value of xx for Perimeters

In this problem, you are given triangle ABCABC with sides proportional to xx, 2x2x, and 3x3x, and you know the total perimeter is 36.

The sum of the sides is: x+2x+3x=6xx + 2x + 3x = 6x Setting this equal to 36: 6x=36    x=66x = 36 \implies x = 6

Hence, the correct answer is 4 (minimum value). Option C.


Would you like further details on any of these solutions?

5 Related Questions:

  1. How do you calculate the area of a parallelogram given its dimensions?
  2. What is the proportionality theorem in triangles?
  3. How can you use triangle height to compare areas in similar triangles?
  4. What are the key properties of a rectangle and triangle areas within it?
  5. How do you approach solving for unknowns in perimeter-related geometry problems?

Tip: Always start by breaking down complex figures into simpler parts to solve area problems more easily.

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Math Problem Analysis

Mathematical Concepts

Geometry
Area Calculation
Triangles
Parallelograms
Ratios

Formulas

Area of a rectangle = length × width
Area of a triangle = (1/2) × base × height
Ratio of areas in similar triangles
Perimeter = sum of side lengths

Theorems

Triangle Proportionality Theorem
Properties of Parallelograms
Area of Similar Triangles

Suitable Grade Level

Grades 7-9