Math Problem Statement

  1. Let ABCD be a square and P be a point on segment AB. Segments CP and BD intersect at Q, and BD is extended beyond B to a point S. Finally, T is the intersection of line CP and the line through S parallel to AB. If AB = 18 and PT = 2CQ, what is the area of quadrilateral PST?

Solution

To solve this problem, we proceed with the following steps:

Step 1: Assign coordinates to the square

Let the square ABCDABCD be on the coordinate plane with:

  • A=(0,0)A = (0, 0),
  • B=(18,0)B = (18, 0),
  • C=(18,18)C = (18, 18),
  • D=(0,18)D = (0, 18).

Let P=(x,0)P = (x, 0) on segment ABAB, where 0x180 \leq x \leq 18.

Step 2: Equations of lines

  • Line CPCP: Slope is 18x18\frac{18}{x - 18}, so the equation of CPCP is: y0=18x18(x18)    y=18x18(Xx).y - 0 = \frac{18}{x - 18} (x - 18) \quad \implies \quad y = \frac{18}{x - 18} (X - x).

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Math Problem Analysis

Mathematical Concepts

Geometry
Coordinate Geometry
Line Equations
Similar Triangles

Formulas

Equation of a line in slope-intercept form
Distance formula

Theorems

Intercept Theorem
Area of quadrilateral formula

Suitable Grade Level

Grades 10-12