Math Problem Statement

Suppose 2k + 7, 1-k, and k-7 are consecutive terms of a geometric sequence. Find the possible values of k. In each case, state the common ratio r.

Solution

In a geometric sequence, the ratio of any two consecutive terms is constant. Let the given terms be a=2k+7a = 2k + 7, b=1kb = 1 - k, and c=k7c = k - 7. For these terms to be in a geometric sequence, the following condition must hold:

ba=cb\frac{b}{a} = \frac{c}{b}

Step 1: Write the condition for the geometric sequence

1k2k+7=k71k\frac{1 - k}{2k + 7} = \frac{k - 7}{1 - k}

Cross-multiply: (1k)2=(2k+7)(k7)(1 - k)^2 = (2k + 7)(k - 7)

Step 2: Expand both sides

(1k)2=12k+k2(1 - k)^2 = 1 - 2k + k^2 (2k+7)(k7)=2k214k+7k49=2k27k49(2k + 7)(k - 7) = 2k^2 - 14k + 7k - 49 = 2k^2 - 7k - 49

Equating these: 12k+k2=2k27k491 - 2k + k^2 = 2k^2 - 7k - 49

Step 3: Simplify the quadratic equation

Rearrange all terms to one side: 0=2k27k49(12k+k2)0 = 2k^2 - 7k - 49 - (1 - 2k + k^2) 0=2k27k491+2kk20 = 2k^2 - 7k - 49 - 1 + 2k - k^2 0=k25k500 = k^2 - 5k - 50

Step 4: Solve the quadratic equation

The equation is: k25k50=0k^2 - 5k - 50 = 0

Using the quadratic formula: k=b±b24ac2a,a=1,b=5,c=50k = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}, \quad a = 1, b = -5, c = -50 k=(5)±(5)24(1)(50)2(1)k = \frac{-(-5) \pm \sqrt{(-5)^2 - 4(1)(-50)}}{2(1)} k=5±25+2002k = \frac{5 \pm \sqrt{25 + 200}}{2} k=5±2252k = \frac{5 \pm \sqrt{225}}{2} k=5±152k = \frac{5 \pm 15}{2}

Thus: k=5+152=10ork=5152=5k = \frac{5 + 15}{2} = 10 \quad \text{or} \quad k = \frac{5 - 15}{2} = -5

Step 5: Find the common ratio rr for each case

  1. Case 1: k=10k = 10

    • Terms: 2k+7=272k + 7 = 27, 1k=91 - k = -9, k7=3k - 7 = 3
    • Common ratio: r=ba=927=13r = \frac{b}{a} = \frac{-9}{27} = -\frac{1}{3}
  2. Case 2: k=5k = -5

    • Terms: 2k+7=32k + 7 = -3, 1k=61 - k = 6, k7=12k - 7 = -12
    • Common ratio: r=ba=63=2r = \frac{b}{a} = \frac{6}{-3} = -2

Final Answer:

  • For k=10k = 10: r=13r = -\frac{1}{3}
  • For k=5k = -5: r=2r = -2

Would you like a more detailed explanation of any step? 😊


Related Questions:

  1. How can the quadratic formula be applied to other geometric sequences?
  2. What are some real-world applications of geometric sequences?
  3. How do the signs of terms in a geometric sequence affect the common ratio?
  4. Can kk take complex values in this scenario? Why or why not?
  5. What happens if the sequence is arithmetic instead of geometric?

Tip: Always double-check your solutions in sequences by recalculating the ratios to confirm the pattern!

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Math Problem Analysis

Mathematical Concepts

Geometric Sequences
Quadratic Equations
Algebra

Formulas

Geometric sequence ratio condition: b/a = c/b
Quadratic formula: k = (-b ± √(b² - 4ac)) / 2a

Theorems

Geometric Sequence Ratio Theorem
Quadratic Formula

Suitable Grade Level

Grades 9-11