Math Problem Statement
Suppose 2k + 7, 1-k, and k-7 are consecutive terms of a geometric sequence. Find the possible values of k. In each case, state the common ratio r.
Solution
In a geometric sequence, the ratio of any two consecutive terms is constant. Let the given terms be , , and . For these terms to be in a geometric sequence, the following condition must hold:
Step 1: Write the condition for the geometric sequence
Cross-multiply:
Step 2: Expand both sides
Equating these:
Step 3: Simplify the quadratic equation
Rearrange all terms to one side:
Step 4: Solve the quadratic equation
The equation is:
Using the quadratic formula:
Thus:
Step 5: Find the common ratio for each case
-
Case 1:
- Terms: , ,
- Common ratio:
-
Case 2:
- Terms: , ,
- Common ratio:
Final Answer:
- For :
- For :
Would you like a more detailed explanation of any step? 😊
Related Questions:
- How can the quadratic formula be applied to other geometric sequences?
- What are some real-world applications of geometric sequences?
- How do the signs of terms in a geometric sequence affect the common ratio?
- Can take complex values in this scenario? Why or why not?
- What happens if the sequence is arithmetic instead of geometric?
Tip: Always double-check your solutions in sequences by recalculating the ratios to confirm the pattern!
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Math Problem Analysis
Mathematical Concepts
Geometric Sequences
Quadratic Equations
Algebra
Formulas
Geometric sequence ratio condition: b/a = c/b
Quadratic formula: k = (-b ± √(b² - 4ac)) / 2a
Theorems
Geometric Sequence Ratio Theorem
Quadratic Formula
Suitable Grade Level
Grades 9-11
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