Math Problem Statement

The term-to-term rule for a sequence is to start at 4 and multiply by 5 each time. a) Work out the first three terms of the sequence. b) Write the nth term rule for the sequence in the form a × r^(n-1).

Solution

Let's solve this step by step.


Part (a): Work out the first three terms of the sequence.

The term-to-term rule states:

  • Start at 4 and multiply by 5 each time.

The first term is: T1=4T_1 = 4

The second term is: T2=4×5=20T_2 = 4 \times 5 = 20

The third term is: T3=20×5=100T_3 = 20 \times 5 = 100

Thus, the first three terms are: 4,20,1004, 20, 100


Part (b): Write the nthn^{\text{th}} term rule in the form a×r(n1)a \times r^{(n-1)}.

The general form for a geometric sequence is: Tn=a×r(n1)T_n = a \times r^{(n-1)} where:

  • aa is the first term,
  • rr is the common ratio,
  • nn is the term number.

From the problem:

  • a=4a = 4 (first term),
  • r=5r = 5 (common ratio).

Substitute these into the formula: Tn=4×5(n1)T_n = 4 \times 5^{(n-1)}


Final Answers:

a) The first three terms are: 4, 20, 100.
b) The nthn^{\text{th}} term rule is: Tn=4×5(n1).T_n = 4 \times 5^{(n-1)}.


Do you need further clarification on any part? Let me know!


Related Questions:

  1. What are the first five terms of the sequence?
  2. How can you verify that a sequence is geometric?
  3. What is the 6th term of this sequence?
  4. How do you calculate the sum of the first nn terms of a geometric sequence?
  5. What happens to the sequence if the common ratio is less than 1?

Tip: In geometric sequences, the ratio between consecutive terms remains constant, which makes it easy to identify the next terms!

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Geometric Sequence
Exponential Growth
nth Term of a Sequence

Formulas

T_n = a × r^(n-1)

Theorems

Geometric Sequence Formula

Suitable Grade Level

Grades 8-10