Math Problem Statement

The numbers 2, 3x, and (x + 16) are the first three terms of a geometric sequence. (a) Find the possible values of x (b) Find the possible values of the 4th term of the geometric sequence.

Solution

The question involves a geometric sequence where the first three terms are 22, 3x3x, and x+16x + 16.

Part (a) - Find the possible values of xx

In a geometric sequence, the ratio between consecutive terms is constant. Let the common ratio be rr.

For the terms 22, 3x3x, and x+16x + 16, the common ratio between the first two terms is: r=3x2r = \frac{3x}{2} The common ratio between the second and third terms is: r=x+163xr = \frac{x + 16}{3x} Since the ratio between consecutive terms is the same, we can set these two expressions equal: 3x2=x+163x\frac{3x}{2} = \frac{x + 16}{3x} Now we solve for xx.

Cross-multiply to eliminate the fractions: (3x)(3x)=2(x+16)(3x)(3x) = 2(x + 16) 9x2=2x+329x^2 = 2x + 32 Rearrange the equation: 9x22x32=09x^2 - 2x - 32 = 0 Now, solve this quadratic equation using the quadratic formula: x=(2)±(2)24(9)(32)2(9)x = \frac{-(-2) \pm \sqrt{(-2)^2 - 4(9)(-32)}}{2(9)} x=2±4+115218x = \frac{2 \pm \sqrt{4 + 1152}}{18} x=2±115618x = \frac{2 \pm \sqrt{1156}}{18} x=2±3418x = \frac{2 \pm 34}{18} Thus, the two possible values for xx are: x=2+3418=3618=2x = \frac{2 + 34}{18} = \frac{36}{18} = 2 or x=23418=3218=169x = \frac{2 - 34}{18} = \frac{-32}{18} = -\frac{16}{9}

Part (b) - Find the possible values of the 4th term

For the fourth term, we need to multiply the third term by the common ratio rr.

  • If x=2x = 2:

    • First three terms are 22, 66, and 1818 (since 2+16=182 + 16 = 18).
    • The common ratio r=62=3r = \frac{6}{2} = 3.
    • The fourth term is 18×3=5418 \times 3 = 54.
  • If x=169x = -\frac{16}{9}:

    • First three terms are 22, 163-\frac{16}{3}, and 1289\frac{128}{9}.
    • The common ratio r=1632=83r = \frac{-\frac{16}{3}}{2} = -\frac{8}{3}.
    • The fourth term is 1289×83=102427\frac{128}{9} \times -\frac{8}{3} = -\frac{1024}{27}.

Final Answers:

  • Possible values of xx: 22 or 169-\frac{16}{9}.
  • Possible values of the 4th term: 5454 or 102427-\frac{1024}{27}.

Would you like any more details or have any questions?

Here are some related questions:

  1. How do you find the general term of a geometric sequence?
  2. What is the difference between an arithmetic and a geometric sequence?
  3. Can a geometric sequence have a common ratio of 0?
  4. How do you find the sum of the first nn terms of a geometric series?
  5. What happens when the common ratio of a geometric sequence is negative?

Tip: In a geometric sequence, knowing the ratio allows you to quickly determine any term in the sequence using the formula an=a1rn1a_n = a_1 \cdot r^{n-1}.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Geometric Sequence
Algebra
Quadratic Equations

Formulas

Common ratio formula: r = a2 / a1 = a3 / a2
Quadratic equation: ax^2 + bx + c = 0
Quadratic formula: x = [-b ± sqrt(b^2 - 4ac)] / 2a

Theorems

Quadratic formula

Suitable Grade Level

Grades 9-12