what's the general equation of this hyperbola:
(y+4)^2/16 - (x+3)^2/4 = 1

The given equation of the hyperbola is:

\[
\frac{(y+4)^2}{16} - \frac{(x+3)^2}{4} = 1
\]

This is in the standard form of a vertical hyperbola:

\[
\frac{(y-k)^2}{a^2} - \frac{(x-h)^2}{b^2} = 1
\]

Here, the center of the hyperbola is \((h, k)\), and \(a^2\) and \(b^

what's the general equation of this hyperbola: (y+4)^2/16 - (x+3)^2/4 = 1

Discover the general equation of the hyperbola (y+4)^2/16 - (x+3)^2/4 = 1, including detailed explanations of hyperbolas, their standard forms, and the relationship between coefficients and the hyperbola's shape. Perfect for students in Grades 10-12 studying Conic Sections.

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