Math Problem Statement

Use the Euclidean algorithm to hand-calculate the greatest common divisor for the integers given below. 479 and 1,469 Step 1: Find q1 and r1 so that 1,469 = 479 · q1 + r1, where 0 ≤ r1 < 479. Then 32 = 1,469 − 479 · q1. Step 2: Find q2 and r2 so that 479 = r1 · q2 + r2, where 0 ≤ r2 < r1. Then = 479 −

· q2. Step 3: Find q3 and r3 so that r1 = r2 · q3 + r3, where 0 ≤ r3 < r2. Then

· q3. Step 4: Find q4 and r4 so that r2 = r3 · q4 + r4, where 0 ≤ r4 < r3. Then

· q4. Step 5: Conclude that gcd(1,469, 479) = .

Solution

To find the greatest common divisor (gcd) of 1,469 and 479 using the Euclidean algorithm, let's follow the steps provided. We want to apply the division algorithm repeatedly until we reach a remainder of 0.

Step 1:

We begin by dividing 1,469 by 479.

1,469=479q1+r11,469 = 479 \cdot q_1 + r_1

Perform the division:

1,469÷479=3 (quotient)1,469 \div 479 = 3 \text{ (quotient)}

Now calculate the remainder r1r_1:

1,4694793=1,4691,437=321,469 - 479 \cdot 3 = 1,469 - 1,437 = 32

Thus, we have:

1,469=4793+321,469 = 479 \cdot 3 + 32

So, q1=3q_1 = 3 and r1=32r_1 = 32.

Step 2:

Next, we divide 479 by 32.

479=32q2+r2479 = 32 \cdot q_2 + r_2

Perform the division:

479÷32=14 (quotient)479 \div 32 = 14 \text{ (quotient)}

Now calculate the remainder r2r_2:

4793214=479448=31479 - 32 \cdot 14 = 479 - 448 = 31

Thus, we have:

479=3214+31479 = 32 \cdot 14 + 31

So, q2=14q_2 = 14 and r2=31r_2 = 31.

Step 3:

Now, divide 32 by 31.

32=31q3+r332 = 31 \cdot q_3 + r_3

Perform the division:

32÷31=1 (quotient)32 \div 31 = 1 \text{ (quotient)}

Now calculate the remainder r3r_3:

32311=3231=132 - 31 \cdot 1 = 32 - 31 = 1

Thus, we have:

32=311+132 = 31 \cdot 1 + 1

So, q3=1q_3 = 1 and r3=1r_3 = 1.

Step 4:

Now, divide 31 by 1.

31=1q4+r431 = 1 \cdot q_4 + r_4

Perform the division:

31÷1=31 (quotient)31 \div 1 = 31 \text{ (quotient)}

Now calculate the remainder r4r_4:

31131=3131=031 - 1 \cdot 31 = 31 - 31 = 0

Thus, we have:

31=131+031 = 1 \cdot 31 + 0

So, q4=31q_4 = 31 and r4=0r_4 = 0.

Conclusion:

Since the remainder is now 0, the gcd is the last non-zero remainder, which is 1.

Therefore, the gcd(1,469, 479) = 1.

Would you like more details on any of these steps or another related topic?

Here are 5 related questions to expand your understanding:

  1. How does the Euclidean algorithm work for larger numbers?
  2. What is the difference between gcd and lcm (least common multiple)?
  3. Can the Euclidean algorithm be used for more than two numbers?
  4. How can the extended Euclidean algorithm find linear combinations?
  5. What are practical applications of the gcd in number theory?

Tip: The Euclidean algorithm is very efficient and works even for large numbers, with only a few iterations required to find the gcd.

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Math Problem Analysis

Mathematical Concepts

Number Theory
Greatest Common Divisor (GCD)
Euclidean Algorithm

Formulas

Division algorithm: a = b · q + r, where 0 ≤ r < b

Theorems

Euclidean Algorithm

Suitable Grade Level

Grades 10-12