Math Problem Statement

Let S = {Jan,Feb,Mar,April,May} be a set of months of a particular year. Consider the following relation on the set S. R1 = {(Feb,Feb),(March,April),(April,March),(March,March)} and R2 = {(Jan,Jan),(Feb,Feb),(March, March),(April,April),(May,May)}. How to know it's injective, subjective or not a function at all?

Solution

To determine whether R1R1 and R2R2 are injective, surjective, or functions at all, we need to first check if they satisfy the definition of a function.

Definition of a function:

A relation is a function if every element in the domain (set SS) is mapped to exactly one element in the codomain. Specifically, for each element xx in the domain, there must be one and only one pair (x,y)(x, y) in the relation.

Relation R1R1:

  • Relation R1R1 = {(Feb, Feb), (March, April), (April, March), (March, March)}
  1. Is R1R1 a function?
    • The domain of the relation R1R1 should contain all elements from SS. Let's check:
      • S={Jan,Feb,March,April,May}S = \{\text{Jan}, \text{Feb}, \text{March}, \text{April}, \text{May}\}
      • In R1R1, we have Feb, March, and April as elements of the domain, but Jan and May are missing.
      • Additionally, March

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Math Problem Analysis

Mathematical Concepts

Set Theory
Relations and Functions

Formulas

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Theorems

Definition of a function
Injective Function
Surjective Function

Suitable Grade Level

Grades 10-12