Math Problem Statement

Find the function value f(x) = ∛x + 8 when x = 1.

Solution

To solve the problem, we need to find the value of the function f(x)=x3+8f(x) = \sqrt[3]{x} + 8 when x=1x = 1.

Given: f(x)=x3+8f(x) = \sqrt[3]{x} + 8 We need to evaluate: f(1)=13+8f(1) = \sqrt[3]{1} + 8

Step 1: Compute the cube root of 1. 13=1\sqrt[3]{1} = 1

Step 2: Add 8 to the result. f(1)=1+8=9f(1) = 1 + 8 = 9

So, the function value f(1)=9f(1) = 9, not 12 as shown in the example.

Would you like more details or have any other questions?

Here are 5 related questions to consider:

  1. What is f(8)f(8) for the same function?
  2. How would you find the value of f(x)f(x) if x=1x = -1?
  3. What does the cube root function look like graphically?
  4. How does adding 8 to the cube root function shift its graph?
  5. How would the function change if it were f(x)=x13+8f(x) = \sqrt[3]{x - 1} + 8?

Tip: When solving function problems, always ensure to substitute the variable correctly and simplify step by step to avoid errors.

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Math Problem Analysis

Mathematical Concepts

Algebra
Functions
Cube Roots

Formulas

f(x) = ∛x + 8

Theorems

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Suitable Grade Level

Grades 9-10