Math Problem Statement

f(x)=^7 √ 8x +5

Solution

Ah, I see now! You are defining the function f(x)f(x) as:

f(x)=8x7+5f(x) = \sqrt[7]{8x} + 5

This means that f(x)f(x) consists of two parts:

  1. 8x7\sqrt[7]{8x}: The 7th root of 8x8x.
  2. +5+ 5: A constant that is added after computing the 7th root.

Explanation

  • 7th Root: The 7th root of a number yy is the value that, when raised to the power of 7, gives yy. So, 8x7\sqrt[7]{8x} represents the number that, when raised to the 7th power, equals 8x8x.

  • Addition: After computing the 7th root, you add 5 to the result.

Example Evaluation

For example, if you wanted to evaluate f(x)f(x) at x=1x = 1, you would do the following:

[ f(1) = \sqrt[7]{8(1)} + 5 = \sqrt[7]{8} + 5 ]

The 7th root of 8 is approximately 1.1547, so:

f(1)1.1547+5=6.1547f(1) \approx 1.1547 + 5 = 6.1547

Do you need more help with:

  • Evaluating the function for different values of xx?
  • Understanding its graph?
  • Finding its derivative?

Here are 5 related questions:

  1. How does the function f(x)=8x7+5f(x) = \sqrt[7]{8x} + 5 behave as xx increases?
  2. What is the domain of f(x)f(x)?
  3. What is the derivative of f(x)f(x)?
  4. What happens to f(x)f(x) as xx approaches 0?
  5. How would you graph this function?

Tip: When working with roots, odd roots (like the 7th root) are defined for both positive and negative values of the argument, so the domain of the function can include negative xx.

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Math Problem Analysis

Mathematical Concepts

Roots
Functions
Arithmetic operations

Formulas

Seventh root formula: \( \sqrt[7]{y} = y^{\frac{1}{7}} \)

Theorems

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Suitable Grade Level

Grades 10-12