Math Problem Statement

Solve three math problems related to functions, geometry of a rectangle, and coefficient comparison of rational functions.

Solution

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Problem 1

If f(x)=axr+bf(x) = ax^r + b passes through the point A(1,2)A(1, -2) and is symmetric around the origin, find ba\frac{b}{a}.

  • Symmetry around the origin means f(x)=f(x)f(-x) = -f(x).

  • Substituting this property into f(x)f(x):
    a(x)r+b=(axr+b)a(-x)^r + b = -(ax^r + b)
    Simplifying:
    (1)raxr+b=axrb(-1)^r ax^r + b = -ax^r - b
    Therefore:
    (1)ra=a(-1)^r a = -a and b=bb = -b.
    From b=bb = -b, we find b=0b = 0.

  • Substituting A(1,2)A(1, -2) into f(x)f(x):
    2=a(1)r+0-2 = a(1)^r + 0
    a=2a = -2.

Thus, ba=02=0\frac{b}{a} = \frac{0}{-2} = 0.

Answer: Option 4.


Problem 2

Given rectangle ABCDABCD with width 8 and height 6, and ACAC as a diagonal, BB is at an angle bisector, and EE lies on ACAC. Find the length of AEAE.

  • The rectangle dimensions are given as 8 (width) and 6 (height).
  • Diagonal AC=82+62=64+36=10AC = \sqrt{8^2 + 6^2} = \sqrt{64 + 36} = 10.
  • BB lies on the angle bisector, and EE divides ACAC into segments proportional to the rectangle's sides.

Let the ratio of division of ACAC be proportional to 8:6=4:38:6 = 4:3.

  • Therefore:
    AE=44+3AC=4710=407AE = \frac{4}{4+3} \cdot AC = \frac{4}{7} \cdot 10 = \frac{40}{7}.

Answer: Option 3.


Problem 3

If f(x)=Fx+dxbf(x) = \frac{Fx + d}{x - b} and g(x)=2xbg(x) = \frac{2}{x - b}, find the difference of coefficients that leads to equal functions.

  • Comparing f(x)f(x) and g(x)g(x):
    Fx+dxb=2xb\frac{Fx + d}{x - b} = \frac{2}{x - b}.
    Equating the numerators since the denominators are the same:
    Fx+d=2Fx + d = 2.
    • Coefficient of xx is FF, and the constant term is dd.

From Fx+d=2Fx + d = 2:
F=0F = 0 and d=2d = 2.
The difference between coefficients Fd=02=2F - d = 0 - 2 = -2.

Answer: Option 4.


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Related Questions

  1. What does symmetry around the origin imply in a function graphically?
  2. How do you derive the formula for diagonals in a rectangle?
  3. Why is the division of the diagonal ACAC in the ratio of rectangle sides?
  4. How do you compare two rational functions to find coefficients?
  5. What are the key steps in solving problems involving ratios in geometry?

Tip: When working with ratios, always reduce to the simplest form before calculating.

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Math Problem Analysis

Mathematical Concepts

Function symmetry
Geometry of rectangles
Ratios and proportionality
Rational functions

Formulas

Symmetry condition: f(-x) = -f(x)
Diagonal of a rectangle: AC = sqrt(width^2 + height^2)
Proportionality: AE = (ratio) * AC

Theorems

Symmetry of odd functions
Pythagoras theorem
Properties of rational functions

Suitable Grade Level

Grades 9-11