I can see the image you uploaded contains several functions that need to be evaluated. Let's break them down and solve each step by step.

1. First Box:

$f(y) = 3 - \sqrt{y}, \quad f(36)$

We substitute $y = 36$: $f(36) = 3 - \sqrt{36} = 3 - 6 = -3$

2. Second Box:

$f(x) = \frac{|3x|}{x}, \quad f(-6)$

We substitute $x = -6$: $f(-6) = \frac{|3(-6)|}{-6} = \frac{18}{-6} = -3$

3. Third Box:

$f(x) = 2x + 2, \quad f(-8)$

Substituting $x = -8$: $f(-8) = 2(-8) + 2 = -16 + 2 = -14$

4. Fourth Box:

$f(x) = -x^2 + 2, \quad f(-4)$

Substituting $x = -4$: $f(-4) = -(-4)^2 + 2 = -16 + 2 = -14$

5. Fifth Box:

$f(t) = \frac{2t^2 + 8}{t}, \quad f(4)$

Substituting $t = 4$: $f(4) = \frac{2(4)^2 + 8}{4} = \frac{2(16) + 8}{4} = \frac{32 + 8}{4} = \frac{40}{4} = 10$

6. Sixth Box:

$f(x) = \sqrt{x^2 - 17} + 2, \quad f(-9)$

Substituting $x = -9$: $f(-9) = \sqrt{(-9)^2 - 17} + 2 = \sqrt{81 - 17} + 2 = \sqrt{64} + 2 = 8 + 2 = 10$

7. Seventh Box:

$f(x) = -|x|^3 + 2, \quad f(-2)$

Substituting $x = -2$: $f(-2) = -|-2|^3 + 2 = -(2^3) + 2 = -(8) + 2 = -8 + 2 = -6$

8. Eighth Box:

$f(t) = -\sqrt{t^2 + 11}, \quad f(5)$

Substituting $t = 5$: $f(5) = -\sqrt{(5)^2 + 11} = -\sqrt{25 + 11} = -\sqrt{36} = -6$

Summary of Results:

1. $f(36) = -3$
2. $f(-6) = -3$
3. $f(-8) = -14$
4. $f(-4) = -14$
5. $f(4) = 10$
6. $f(-9) = 10$
7. $f(-2) = -6$
8. $f(5) = -6$

Would you like a detailed explanation of any specific solution? Here are five related questions you could explore:

1. What are the properties of absolute value functions?
2. How do square root functions behave for positive and negative values?
3. What are the implications of squaring negative values in a function?
4. Can you explain how to simplify fractional expressions?
5. How do you evaluate composite functions like those involving square roots and absolute values?

Tip: Always check for domain restrictions when dealing with square roots and denominators to avoid undefined expressions.