To find $(f - g)(x)$, we need to subtract the function $g(x)$ from $f(x)$.

Given:

• $f(x) = x - 8$
• $g(x) = \sqrt{x} + 2$

Now, subtract $g(x)$ from $f(x)$:

$(f - g)(x) = f(x) - g(x)$ $(f - g)(x) = (x - 8) - (\sqrt{x} + 2)$ Simplify:

$(f - g)(x) = x - 8 - \sqrt{x} - 2$ $(f - g)(x) = x - \sqrt{x} - 10$

Thus, $(f - g)(x) = x - \sqrt{x} - 10$.

Would you like further clarification or additional examples?

Here are five related questions:

1. What is $(f + g)(x)$?
2. Can you find $(f \cdot g)(x)$?
3. What is $(f \div g)(x)$, assuming $g(x) \neq 0$?
4. What is the domain of $(f - g)(x)$?
5. How does the behavior of $(f - g)(x)$ change as $x \to \infty$?

Tip: Always remember to check the domain restrictions for square roots or divisions when working with composite functions!