Math Problem Statement

fx is increasing at xo means

Solution

When f(x)f(x) is said to be increasing at x0x_0, it means that the slope of the function f(x)f(x) at x0x_0 is positive. Mathematically, this is characterized by the derivative f(x0)f'(x_0) being positive:

f(x0)>0f'(x_0) > 0

This implies that as xx moves slightly to the right of x0x_0 (x>x0x > x_0), the function values f(x)f(x) increase, i.e., f(x)>f(x0)f(x) > f(x_0). Similarly, for values of xx slightly to the left of x0x_0 (x<x0x < x_0), the function values f(x)f(x) are less than f(x0)f(x_0).

In more intuitive terms:

  • Graphically: The curve of f(x)f(x) is sloping upwards at x0x_0.
  • Numerically: The rate of change of f(x)f(x) with respect to xx at x0x_0 is positive.

Would you like a deeper explanation, visualizations, or examples?


Expanding Questions:

  1. How is the derivative used to determine intervals of increase and decrease for a function?
  2. What is the difference between a function being increasing and being strictly increasing?
  3. How does the second derivative affect the behavior of f(x)f(x) when it is increasing?
  4. Can a function be increasing at a point where the derivative does not exist? If so, how?
  5. How would you test whether a function is increasing over an interval instead of just at a point?

Tip:

To identify increasing or decreasing behavior, always calculate and analyze the first derivative.

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Math Problem Analysis

Mathematical Concepts

Calculus
Derivatives
Function Behavior

Formulas

f'(x_0) > 0

Theorems

First Derivative Test

Suitable Grade Level

Grades 11-12