Math Problem Statement

Evaluate the functions f(x) for specific values: f(1), f(4), f(-3), f(8), and f(-2) for given functions.

Solution

Let's solve each function for the given values step by step:

  1. Find f(1)f(1): Function: f(x)=2x5+2f(x) = -2|x - 5| + 2

    Substituting x=1x = 1: f(1)=215+2=24+2=2(4)+2=8+2=6f(1) = -2|1 - 5| + 2 = -2| -4 | + 2 = -2(4) + 2 = -8 + 2 = -6

    Result: f(1)=6f(1) = -6


  1. Find f(4)f(4): Function: f(x)=x210x+23f(x) = x^2 - 10x + 23

    Substituting x=4x = 4: f(4)=(4)210(4)+23=1640+23=24+23=1f(4) = (4)^2 - 10(4) + 23 = 16 - 40 + 23 = -24 + 23 = -1

    Result: f(4)=1f(4) = -1


  1. Find f(3)f(-3): Function: f(x)=x2+1f(x) = -x^2 + 1

    Substituting x=3x = -3: f(3)=(3)2+1=(9)+1=9+1=8f(-3) = -(-3)^2 + 1 = -(9) + 1 = -9 + 1 = -8

    Result: f(3)=8f(-3) = -8


  1. Find f(8)f(8): Function: f(x)=4x114f(x) = |4x - 1| - 14

    Substituting x=8x = 8: f(8)=4(8)114=32114=3114=3114=17f(8) = |4(8) - 1| - 14 = |32 - 1| - 14 = |31| - 14 = 31 - 14 = 17

    Result: f(8)=17f(8) = 17


  1. Find f(2)f(-2) (for two different functions):
    • First Function: f(x)=x3+5f(x) = -x^3 + 5

      Substituting x=2x = -2: f(2)=(2)3+5=(8)+5=8+5=13f(-2) = -(-2)^3 + 5 = -( -8 ) + 5 = 8 + 5 = 13

      Result: f(2)=13f(-2) = 13

    • Second Function: f(x)=x2+4x1f(x) = x^2 + 4x - 1

      Substituting x=2x = -2: f(2)=(2)2+4(2)1=481=41=5f(-2) = (-2)^2 + 4(-2) - 1 = 4 - 8 - 1 = -4 - 1 = -5

      Result: f(2)=5f(-2) = -5


Final Answers:

  1. f(1)=6f(1) = -6
  2. f(4)=1f(4) = -1
  3. f(3)=8f(-3) = -8
  4. f(8)=17f(8) = 17
  5. f(2)=13f(-2) = 13 (first function), f(2)=5f(-2) = -5 (second function)

Would you like a breakdown of any particular step?


Related Questions:

  1. What happens to the value of f(x)f(x) as xx approaches a large positive number in f(x)=4x114f(x) = |4x - 1| - 14?
  2. How does the graph of f(x)=x3+5f(x) = -x^3 + 5 behave for large negative values of xx?
  3. What is the vertex of the parabola f(x)=x210x+23f(x) = x^2 - 10x + 23?
  4. How does the absolute value impact the function f(x)=2x5+2f(x) = -2|x - 5| + 2?
  5. What is the domain and range of f(x)=x2+1f(x) = -x^2 + 1?

Tip:

Always double-check your substitutions, especially when dealing with absolute values and negative exponents, as small mistakes can lead to incorrect results.

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Math Problem Analysis

Mathematical Concepts

Function evaluation
Absolute values
Quadratic functions
Cubic functions

Formulas

f(x) = -2|x - 5| + 2
f(x) = x^2 - 10x + 23
f(x) = -x^2 + 1
f(x) = |4x - 1| - 14
f(x) = -x^3 + 5
f(x) = x^2 + 4x - 1

Theorems

Properties of absolute value
Quadratic function behavior
Cubic function evaluation

Suitable Grade Level

Grades 8-10