We are given the functions $f(x) = 3x - 1$ and $h(x) = -x + 1$, and asked to find $(h \circ f)(4)$, which means we need to find $h(f(4))$.

Step-by-step solution:

1. Find $f(4)$: $f(x) = 3x - 1$ Substitute $x = 4$: $f(4) = 3(4) - 1 = 12 - 1 = 11$

2. Find $h(f(4)) = h(11)$: $h(x) = -x + 1$ Substitute $x = 11$: $h(11) = -(11) + 1 = -11 + 1 = -10$

Thus, $(h \circ f)(4) = -10$.

Would you like further explanation or details on any step?

Here are 5 related questions:

1. What is $(f \circ h)(4)$?
2. How do you find the composition of two functions in general?
3. What is the result of $(h \circ f)(x)$ for a general $x$?
4. If $f(x) = 2x + 3$ and $h(x) = x^2 - 1$, what is $(h \circ f)(2)$?
5. Can you explain the graphical interpretation of $h(f(x))$?

Tip: Always check your composition step-by-step, starting with the innermost function first!