To find $(f \circ g)(x)$, which is the composition of $f(x)$ and $g(x)$, we substitute $g(x)$ into $f(x)$.

Given:

• $f(x) = x$
• $g(x) = x + 2$

Step-by-step Solution:

1. Substitute $g(x) = x + 2$ into $f(x)$: $f(g(x)) = f(x + 2)$

2. Using $f(x) = x$, replace $x$ in $f(x)$ with $x + 2$: $f(x + 2) = x + 2$

Thus, $(f \circ g)(x) = x + 2$.

Final Answer:

$(f \circ g)(x) = x + 2$

Would you like further details on composition or related examples?
Here are five related questions for practice:

1. If $g(x) = x^2 + 1$, what is $(f \circ g)(x)$ for the same $f(x)$?
2. What is $(g \circ f)(x)$ for the given functions?
3. How does the order of composition affect the result?
4. Solve $(f \circ g \circ h)(x)$ if $h(x) = 2x$.
5. Can $f(x)$ and $g(x)$ be reversed to form an inverse composition?

Tip: Always pay close attention to the order of composition when solving for $(f \circ g)(x)$ and $(g \circ f)(x)$, as they generally differ!