The question provides two functions:

1. $f(x) = 2x + 1$
2. $(f \circ g)(x + 1) = -2x^2 - 4x - 1$

We are asked to find the value of $g(2)$.

Solution

1. First, let's rewrite $(f \circ g)(x + 1)$ as: $(f \circ g)(x + 1) = f(g(x + 1))$ This means that $f(g(x + 1)) = -2x^2 - 4x - 1$.

2. We know that $f(x) = 2x + 1$. Thus, $f(g(x + 1)) = -2x^2 - 4x - 1$.

   To satisfy this, we can assume: $g(x + 1) = ax^2 + bx + c$