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The question provides two functions:

1. \( f(x) = 2x + 1 \)
2. \( (f \circ g)(x + 1) = -2x^2 - 4x - 1 \)

We are asked to find the value of \( g(2) \).

### Solution
1. First, let's rewrite \( (f \circ g)(x + 1) \) as:
   \[
   (f \circ g)(x + 1) = f(g(x + 1))
   \]
   This means that \( f(g(x + 1)) = -2x^2 - 4x - 1 \).

2. We know that \( f(x) = 2x + 1 \). Thus, \( f(g(x + 1)) = -2x^2 - 4x - 1 \).

   To satisfy this, we can assume:
   \[
   g(x + 1) = ax^2 + bx + c
   \]
  

Diketahui fungsi f(x) = 2x + 1 dan (f o g)(x + 1) = -2x^2 - 4x - 1. Nilai g(2) = ?

Learn how to solve for g(2) given the functions f(x) = 2x + 1 and (f ∘ g)(x + 1) = -2x^2 - 4x - 1. This problem covers key algebraic concepts, including function composition and quadratic equations. Suitable for students in Grades 10-12.

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